I forgot but I used to know this one
43 and 44, but it's closer to 43
Answer:
Step-by-step explanation:
In a rectangle, diagonals are equal and bisect each other
BE = AE
6x - 5 = 2x + 7
6x - 2x - 5 = 7
4x - 5 = 7
4x = 7 + 5
4x = 12
x = 12/4
x = 3
AE = 2x + 7
= 2*3 + 7
= 6 + 7
AE = 13
AC = 13 + 13
AC = 26
m∠EBC = 50
In rectangle, each angle is 90
m∠ABE + m∠EBC = 90
m∠ABE + 50 = 90
m∠ABE = 90 - 50
m∠ABE = 40
In rectangle, AB // DC and DB transversal
m∠ECD = m∠ABE { alternate interior angles}
m∠ECD = 40
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
50.24
Step-by-step explanation:
8 is the radius of the circle, so using A=πr^2, the equation would be A=(3.14*8^2)/4
(Dividing by 4 because we are solving for 1/4 of a circle, and substituting pi for 3.14)
(3.14*8^2)=200.96
200.96/4=50.24
