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mylen [45]
3 years ago
8

Fred the clown can create 20 animal balloons every 15 minutes. how much can h make in 6 minutes

Mathematics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

8 animal balloons.

Step-by-step explanation:

Divide 20 by 15 to get how much animal balloons he can make in a minute. That would be 1/3. Then multiply it by 6 to get your answer.

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2.) FIND EF.
Naddika [18.5K]

The measure of EF from the given diagram is 6 units

<h3>Secant secant theorem</h3>

The theorem states that if two secants are drawn from an external point to a circle, then the product of the measures of one secant's external parts is the same as the product of the other external part.

Mathematically according to the given figure;

4(4+2x) = 5(5+x)

Expand

16 + 8x = 25 + 5x

Collect the like terms

8x - 5x = 25 - 16

3x = 9

Divide both sides by 3

3x/3=. 9/3

x = 3

Find EF

EF = 2x

EF = 2(3) = 6

Hence the measure of EF from the given diagram is 6 units

Learn more on secant theorem here: brainly.com/question/10732273

#SPJ1

8 0
2 years ago
8.4^3×4.8^2=<br>can you pleas help​
ira [324]

Answer:

13655.90016

Step-by-step explanation:

8.4^3 \times 4.8^2 \\= 592.704 \times 23.04\\=13655.90016

3 0
3 years ago
If you have any questions please ask away
rjkz [21]
Nicki minaj is a quebeebbenenene
7 0
3 years ago
The amount of radioactive element remaining, r, in a 100mg sample after d days is represented using the equation r=100(1/2) d/5.
Ludmilka [50]

Answer:

   12.94%

Step-by-step explanation:

r = 100(1/2)^(d/5) = 100((1/2)^(1/5))^d ≈ 100(.87055)^d

The daily decrease is 1 - 0.87055 = 0.12944 ≈ 12.94%

4 0
3 years ago
Describe the sampling distribution of Phat. Assume the size of the Population is 25,000. N = 500 P = 0.4 Determine the Mean of t
PIT_PIT [208]

Answer:

0.022

Step-by-step explanation:

Given that :

Population size = 25000

n = 500 ; p = 0.4

Size of random sample (n) = 500

5% of population size : 0.05 * 25000 = 1250

Distribution is normally distributed since n < 5% of population size

Hence, the mean of the distribution = p = 0.4

Standard deviation = √((pq) /n)

q = 1 - p ; q = 1 - 0. 4 = 0.6

Standard deviation = √((0.4 * 0.6) /500)

Standard deviation = 0.0219089

= 0.022

5 0
3 years ago
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