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4 years ago

Least common multiple of 16, 4, and 54

Mathematics

2 answers:

Trava [24]4 years ago

8 0

Answer:

least common multiple would be 2

Juli2301 [7.4K]4 years ago

7 0

Answer:

Step-by-step explanation: Least common multiple of those three number is 2.

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Ms. Taylor earned $18.50 per hour for the first 40 hours she works in a week.She earns 1 1\2 times the amount per hour for each

nalin [4]

18.5•40=740
40•1.5=60
60•5.5=330
740+330=1070
A: $1070

3 0

3 years ago

Read 2 more answers

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

GarryVolchara [31]

Answer:

2y^2. 8/4 = 2 and y^7/y^5 is y^2 i don't know if this is what you completely asked for but here is the answer

Step-by-step explanation:

7 0

3 years ago

Nolan invested $5,300 in an account paying an interest rate of 3.8% compounded

Deffense [45]

Answer:

Step-by-step explanation:

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3 years ago

Given f(x) = 3x - 1 and 9(x) = 2x-3, for which value of x does g(x)=f(2)?

AlekseyPX

Answer:

g(x) = f(2) at x = 4

Step-by-step explanation:

Assuming that you meant g(x) = 2x - 3:

Set f(2) = g(x) and solve the resulting equation for x:

f(2) = 3(2) - 1 = g(x) = 2x - 3.

Thus, 6 - 1 = 2x - 3.

Adding 3 to both sides and simplifying the result, we get:

8 = 2x, or x = 4.

g(x) = f(2) at x = 4.

3 0

3 years ago

A Find the amount compounded annually on Rs 25,000 for 2 years if the rates of

STatiana [176]

Answer:

Amount = Rs. 30250 when Rate = 10%

Amount = Rs. 31360 when Rate = 12%

Step-by-step explanation:

Given

$Principal, P = Rs.\ 25,000$

$Time, t = 2\ years$

$Rate; R_1 = 10\%$

$Rate; R_2 = 12\%$

Number of times (n) = Annually

$n = 1$

Required

Determine the Amount for both Rates

Amount (A) is calculated by:

$A = P(1 + \frac{r}{n})^{nt}$

When Rate = 10%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

$A = 25000 * (1 + \frac{10\%}{1})^{1 * 2}$

$A = 25000 * (1 + \frac{10\%}{1})^{2}$

$A = 25000 * (1 + 10\%)^{2}$

Convert 10% to decimal

$A = 25000 * (1 + 0.10)^{2}$

$A = 25000 * (1.10)^{2}$

$A = 25000 * 1.21$

$A = 30250$

Hence;

Amount = Rs. 30250 when Rate = 10%

When Rate = 12%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

$A = 25000 * (1 + \frac{12\%}{1})^{1 * 2}$

$A = 25000 * (1 + \frac{12\%}{1})^{2}$

$A = 25000 * (1 + 12\%)^{2}$

Convert 12% to decimal

$A = 25000 * (1 + 0.12)^{2}$

$A = 25000 * (1.12)^{2}$

$A = 25000 * 1.2544$

$A = 31360$

Hence;

Amount = Rs. 31360 when Rate = 12%

7 0

3 years ago