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madam [21]
4 years ago
5

Least common multiple of 16, 4, and 54

Mathematics
2 answers:
Trava [24]4 years ago
8 0

Answer:

least common multiple would be 2

Juli2301 [7.4K]4 years ago
7 0

Answer:

Step-by-step explanation: Least common multiple of those three number is 2.

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Ms. Taylor earned $18.50 per hour for the first 40 hours she works in a week.She earns 1 1\2 times the amount per hour for each
nalin [4]
18.5•40=740
40•1.5=60
60•5.5=330
740+330=1070
A: $1070
3 0
3 years ago
Read 2 more answers
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
GarryVolchara [31]

Answer:

2y^2. 8/4 = 2 and y^7/y^5 is y^2 i don't know if this is what you completely asked for but here is the answer

Step-by-step explanation:

7 0
3 years ago
Nolan invested $5,300 in an account paying an interest rate of 3.8% compounded
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Answer:

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Step-by-step explanation:

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3 years ago
Given f(x) = 3x - 1 and 9(x) = 2x-3, for which value of x does g(x)=f(2)?
AlekseyPX

Answer:

g(x) = f(2) at x = 4

Step-by-step explanation:

Assuming that you meant g(x) = 2x - 3:

Set f(2) = g(x) and solve the resulting equation for x:

f(2) = 3(2) - 1 = g(x) = 2x - 3.

Thus,   6 - 1 = 2x - 3.

Adding 3 to both sides and simplifying the result, we get:

8 = 2x, or x = 4.

g(x) = f(2) at x = 4.

3 0
3 years ago
A Find the amount compounded annually on Rs 25,000 for 2 years if the rates of
STatiana [176]

Answer:

Amount = Rs. 30250 when Rate = 10%

<em>Amount = Rs. 31360 when Rate = 12%</em>

Step-by-step explanation:

Given

Principal, P = Rs.\ 25,000

Time, t = 2\ years

Rate; R_1 = 10\%

Rate; R_2 = 12\%

Number of times (n) = Annually

n = 1

Required

Determine the Amount for both Rates

Amount (A) is calculated by:

A = P(1 + \frac{r}{n})^{nt}

When Rate = 10%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

A = 25000 * (1 + \frac{10\%}{1})^{1 * 2}

A = 25000 * (1 + \frac{10\%}{1})^{2}

A = 25000 * (1 + 10\%)^{2}

Convert 10% to decimal

A = 25000 * (1 + 0.10)^{2}

A = 25000 * (1.10)^{2}

A = 25000 * 1.21

A = 30250

Hence;

<em>Amount = Rs. 30250 when Rate = 10%</em>

When Rate = 12%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

A = 25000 * (1 + \frac{12\%}{1})^{1 * 2}

A = 25000 * (1 + \frac{12\%}{1})^{2}

A = 25000 * (1 + 12\%)^{2}

Convert 12% to decimal

A = 25000 * (1 + 0.12)^{2}

A = 25000 * (1.12)^{2}

A = 25000 * 1.2544

A = 31360

Hence;

<em>Amount = Rs. 31360 when Rate = 12%</em>

7 0
3 years ago
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