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3 years ago

Choose the correct solution and graph for the inequality -4x<-12

Mathematics

2 answers:

Nostrana [21]3 years ago

8 0

Answer: [X < 3] treat it as an equal sign
-4x<-12
/-4x /-4x
[X< 3]

Debora [2.8K]3 years ago

5 0

Answer:

Option 1. $x>3$

Step-by-step explanation:

we have

$-4x$

Multiply by $-\frac{1}{4}$ both sides

$x>3$ -----> remember that less change to greater

the solution is the interval------> $(3, infinite)$

All real numbers greater than $3$

The solution of the inequality is the shaded area to the right of the dashed line

The graph in the attached figure

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(50 POINTS) (PLEASE ANSWER THE QUESTION, NOT JUST TRY AND TAKE MY POINTS, I NEED HELP ON THIS SO DO NOT ANSWER IF YOU DO NOT KNO

jarptica [38.1K]

Answer:

No, there is no proportional relationship

Step-by-step explanation:

<u>The proportional relationship is:</u>

y = kx, which is a special form of linear equation, with zero y-intercept

<u>In the given case we have:</u>

y = 4.5x + 10

This is a linear function but not proportional relationship because it has y-intercept, different than zero

8 0

3 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

monitta

Answer:

a) n =1623

b) $ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208$

Step-by-step explanation:

1) Notation and definitions

$n$ random sample taken

$\hat p=0.19$ estimated proportion of customers are not satisfied with the service provided by the local dealer

Confidence =0.96 or 96%

Me= 0.02 represent the margin of error

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 96% of confidence, our significance level would be given by $\alpha=1-0.96=0.04$ and $\alpha/2 =0.02$ . And the critical value would be given by: