a bag contains 6 blue balls 3 green balls and 3 yellow balls. what is the probability of choosing one blue ball then a yellow ba
2 answers:
Answer:
probability of blue ball is 1/2
probability of yellow ball is 1/4
Step-by-step explanation:
We have given 6 blue balls 3 green balls and 3 yellow balls
Total number of balls are: 12
we have to find the probability of choosing a blue ball:
Then the ball was placed in the bag since, it is given replacement
Now, we have to find probability of choosing a yellow ball
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Tan(x) = sin(x) / cos(x)
Csc(x) = 1/ sin(x)
You'll see this better if I use latex.
Now just cancel numerators with denominations. They all disappear. The cancelations leave 1 on both the numerator and denominator.
Csc(x) = 1/ sin(x)
You'll see this better if I use latex.
Now just cancel numerators with denominations. They all disappear. The cancelations leave 1 on both the numerator and denominator.
Hi There!
Since there are 180 school days and Holly missed 7 then she attended
days.
So, to find out the percent of school days she attended school you have to divide 173/180, 173 represents school days she attended or numerator, and 180 represents total school days the denominator. Once you divide 173/180 you should get 0.<span>96111111111, but if you round it, the answer will be 96%.
Steps
1. Divide 173/180= 0.</span>96111111111<span>
2. Round you're answer 0.</span><span>96111111111
</span>
Final Answer- Holly attended 96% percent of school days.
Hope This Helps:)
Since there are 180 school days and Holly missed 7 then she attended
So, to find out the percent of school days she attended school you have to divide 173/180, 173 represents school days she attended or numerator, and 180 represents total school days the denominator. Once you divide 173/180 you should get 0.<span>96111111111, but if you round it, the answer will be 96%.
Steps
1. Divide 173/180= 0.</span>96111111111<span>
2. Round you're answer 0.</span><span>96111111111
</span>
Final Answer- Holly attended 96% percent of school days.
Hope This Helps:)