This question is not complete because is lacks the options for each question.
Complete question
mr. whittaker’s science class uses tide gauges to measure annual variations in water levels at different parts of a river, and then compares those variations to the average annual trend. matea recorded that the water level in one part of the river fell 1.05 millimeters per year for 2.48 years. this data will be compared to the average annual trend, which shows the water level rising 1.8 mm/year.
1) Which number represents the rate at which the water level fell?
a. -1.05 mm/year
b. -1.8 mm/year
c. -2.48 years
d. -2.48 mm/year
2) Which number should the rate be multiplied by to find the total variation in water level?
a. 1.05 mm/year
b. 1.8 mm/year
c. 2.48 years
d. 2.48 mm/year
Answer:
1) Which number represents the rate at which the water level fell?
a. -1.05 mm/year
2) Which number should the rate be multiplied by to find the total variation in water level?
c. 2.48 years
Step-by-step explanation:
Total Variation in the water level is calculated by multiplying the rate at which the water level and number or years at which the rate of the water level fell
From the question, we can see that the rate at which the water level fell is -1.05 mm/year and number of years at which the water level fell is 2.48mm
Hence,Total Variation in the water level is calculated as
-1.05 mm/year × 2.48 years
Total variation in the water level = -2.604mm
Answer:
V = 32
Step-by-step explanation:
Comment
I think you should try this one yourself after I post my answer. Estimation is a very valuable tool -- the more you use it, the handier it gets.
Formulas
pi = 3
V = 4/3 * pi * r^3
Givens
r = 2
pi = 3
Solution
V = 4/3 * pi * r^3 Substitute values for symbols
V = 4/3 * 3 * 2^3 Cancel the 3s
V = 4 * 2^3 Expand the 2s
V = 4 * 2 * 2 * 2 Find V
V = 32
The graph should start at zero, and go up four for every number
Answer:
Step-by-step explanation:5 pounds
35/13.3=2.63. 1.9x2.63=5kg
-8/5
Rise over run aka how many it goes up/down over how many it goes across
