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3 years ago

Can someone lend me a hand pleeeeeeeaaaaseeee :D

Mathematics

2 answers:

Trava [24]3 years ago

7 0

Answer:

2x² + 11

Step-by-step explanation:

f(x) - g(x)

(3x² + 2) - (x² - 9)

Rearrange.

3x² - x² + 2 + 9

Add or subtract like terms.

2x² + 11

MrRissso [65]3 years ago

5 0

Answer:

2x^2 +11

Step-by-step explanation:

f(x) = 3x^2 +2

g(x) = x^2 -9

f(x) - g(x) = 3x^2 +2 - (x^2 -9)

Distribute the minus sign

= 3x^2 +2 -x^2 +9

Combine like terms

= 2x^2 +11

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Two digits are selected with replacement from the digits 1, 2, 3, and 4.

Helen [10]

6 and 8 I believe is the answer

6 0

3 years ago

Looking for someone who can take a look at this question for me:

In-s [12.5K]

There are
7 red balls
8 red balls
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4 0

3 years ago

How can Ari simplify the following expression? StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1

Zielflug [23.3K]

Answer:

$-\frac{8}{3}$

Step-by-step explanation:

Given

$\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}$

Required

Simpify

The very first step is to take LCM of the given expression

$\frac{-10 -4 - 2}{6}$

Perform arithmetic operations o the numerator

$-\frac{16}{6}$

Divide the numerator and denominator by 2

$-\frac{16/2}{6/2}$

$-\frac{8}{3}$

The expression can't be further simplified;

Hence, $\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}$ = $-\frac{8}{3}$

8 0

3 years ago

I need help with number 7 too.

eimsori [14]

Answer:

Look Below

Step-by-step explanation:

m<1 could be 30

m<2 could be 60

m<3 could be 30

3 0

4 years ago

Read 2 more answers

Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.

sdas [7]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation is given below.

$PV = nRT$

The equation can be written as

$\rm PV = \dfrac{m}{M} \ RT\\\\\\MPV = mRT$

Where M is the molar mass, P is the pressure, V is the volume, R is the universal gas constant, T is the temperature, and m is the mass of the gas.

Then the molar mass of a 0.622-gram sample of gas has a volume of 2.4 L at 287 K and 0.850 atm.

V = 2.4 L = 0.0024

P = 0.85 atm = 86126.25 Pa

T = 287 K

m = 0.622

R = 8.314

Then we have

$\begin{aligned} \rm M \times 86126.25 \times 0.0024&= 0.622 \times 8.314 \times 287\\\\\rm M &= 7.18 \end{aligned}$

Then the molar mass of the gas is 7.18.

More about the ideal gas equation link is given below.

brainly.com/question/4147359

#SPJ1

6 0

2 years ago