9 fish (:
5/6 of 54 is 45, so you would need to subtract 45 from 54, which is 9.
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Interquartile range of the old set = 76 - 72 = 4
Interquartile range of the new set = 76 - 73 = 3
IQR of new est < old set.
Answer:
462 + 393 = 855
Step-by-step explanation:
break 462 into hundreds tens in ones do the same with 393. then add the ones together, 2 + 3 = 5. then the tens, 60 + 90 = 150. then the hundreds. 400 + 300 = 700. then assemble your final answer. 700 + 150 + 5 = 855.
0.15 * 20 = 3
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