Answer: 
Step-by-step explanation:
Given: A cubic kilometer=
cubic centimeters
The volume of world’s oceans=
cubic kilometers of water.
⇒ The volume of world’s oceans=
cubic centimeters of water.
Volume of a bucket = 20,000 cubic centimeters of water.
The number of bucket-loads would it take to bucket out the world’s oceans

![\Rightarrow\ n=\frac{1.4\times10^{9+15}}{0.2\times10^5}......[a^n\times a^m=a^{m+n}]\\\Rightarrow\ n=7\times10^{24-5}.....[\frac{a^m}{a^n}=a^{m-n}]\\\Rightyarrow\ n=7\times10^{19}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20n%3D%5Cfrac%7B1.4%5Ctimes10%5E%7B9%2B15%7D%7D%7B0.2%5Ctimes10%5E5%7D......%5Ba%5En%5Ctimes%20a%5Em%3Da%5E%7Bm%2Bn%7D%5D%5C%5C%5CRightarrow%5C%20n%3D7%5Ctimes10%5E%7B24-5%7D.....%5B%5Cfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D%5D%5C%5C%5CRightyarrow%5C%20n%3D7%5Ctimes10%5E%7B19%7D)
hence,
bucketloads would it take to bucket out the world’s oceans.
Answer:
Im sure the answer is 40%
<em>GL Deary</em>
<em>Hope I helped!!!</em>
<em><3</em>
Answer:
P'(7 , -11)
Step-by-step explanation:
what this tells us
(x,y) → ( x+3, y−2)
Is that the value of x of the new point is going to take (x + 3) with respect to the value of x of the other point.
Is that the value of y of the new point is going to take (y - 2) with respect to the value of y of the other point.
P (4,−9)
x = 4
y = -9
P'( x+3, y−2)
x + 3 =
4 + 3 = 7
y - 2 =
-9 - 2 = -11
P'(7 , -11)
Answer:
1/2 + 2/5=2/10 simplified as 1/5 in fraction form