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True [87]
2 years ago
5

Solve the quadratic equation by using either a numeric or a graphic approach.

Mathematics
1 answer:
dimulka [17.4K]2 years ago
4 0

Answer:

C

Step-by-step explanation:

x²-14x-49=0

x²-14x+49=49+49

(x-7)²=98

(x-7)²=49×2

x-7=±7√2

x=7+7√2=7(1+√2)≈7(1+1.414)≈7(2.414)≈16.898≈16.9

or

x=7-7√2=7(1-√2)≈7(1-1.414)≈-7×0.414≈-2.898≈2.9

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A and B

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Which pair of undefined terms is used to define a ray
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3 years ago
What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success​ p? C
charle [14.2K]

Answer:

(D)E[ X ] =np.

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq  x\leq n

E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}

Now,

x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)

Substituting,

E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}

Factoring out the n and one p from the above expression:

E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}

Representing k=x-1 in the above gives us:

E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}

This can then be written by the Binomial Formula as:

E[ X ] = (np) (p +(1 - p))^{n -1 }= np.

5 0
3 years ago
231 ( 40 + 15 ) = 231 x 40 + ------------ x -----------<br><br> which property is this
a_sh-v [17]

Answer:

12705

Step-by-step explanation:

The problem could be solved in two different methods:

1:

231×(55)=12705

2.

231×40+231×15=9240+3465=12705

6 0
2 years ago
Simplify: $\frac{1}{\sqrt{2}+\frac{1}{\sqrt{8}+\sqrt{200}+\frac{1}{\sqrt{18}}}}$.
dmitriy555 [2]

Answer:

Step-by-step explanation:

its no way to answer how u texted it

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2 years ago
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