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rusak2 [61]
3 years ago
14

What is the product? 4 cubed times 4 Superscript negative 3 0 1 4 6

Mathematics
2 answers:
Julli [10]3 years ago
4 0

Answer:

4³ × 4 ^-3

Use the rules of indices

You will get

4^3-3

= 4^0

= 1

Hope this helps

inysia [295]3 years ago
3 0

Answer:

The answer is 1, the second option.

Step-by-step explanation:

Took the test, hope this helps!

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How much is 2/3 cups plus 1 1/4 cups
Schach [20]
  • Answer:

1\frac{11}{12}

  • Step-by-step explanation:

\frac{2}{3}+1\frac{1}{4}=\frac{2}{3}+\frac{5}{4}=\frac{8}{12}+\frac{15}{12}=\\    \\=\frac{8+15}{12}=\frac{23}{12}=1\frac{11}{12}

5 0
3 years ago
The numbers below follow a pattern.
borishaifa [10]

Answer:

0.03, 0.003

Step-by-step explanation:

The decimal moves over one place each time

4 0
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The Campers in cabin D walked 1/6 of the way to Mammoth Mountain. how many miles did the walk ?
svet-max [94.6K]
What is the question ?
4 0
3 years ago
The SAT is standardized to be normally distributed with a mean µ = 500 and a standard deviation σ = 100. What percentage of SAT
Aliun [14]

Answer:

34.134%

68.268%

Step-by-step explanation:

Given that:

Mean (m) = 500

Standard deviation (s) = 100

Percentage between 500 and 600

P(500 < x < 600)

P(x < 600) - P(x < 500)

Z = (x - m) / s

P(x < 600)

Z = (600 - 500) /100 = 1

P(x < 500)

Z = (500 - 500) / 500 = 0

P(Z< 1) - P(Z < 0)

0.84134 - 0.5

= 0.34134

= 0.34134 * 100%

= 34.134%

B.) Between 400 and 600

P(x < 400)

Z = (400 - 500) /100 = - 1

P(x < 600)

Z = (600 - 500) / 500 = 1

P(Z< 1 ) - P(Z < - 1)

0.84134 - 0.15866

= 0.68268

= 0.68268 * 100%

= 68.268%

8 0
3 years ago
F/4 + 16 &lt; 49<br> Solve the inequality
Mnenie [13.5K]

Answer:

f < 132

Step-by-step explanation:

Greetings!

I'm~Isabelle~Williams~and~I~will~be~answering~your~question!

Subtract~16~from~both~sides:

\frac{f}{4} +16-16 < 49-16

Simplify:

\frac{f}{4} < 33

Now,~multiply~both~sides~by~4:

\frac{4f}{4} < 33\times4

f < 132

Hope~my~answer~helps!~Have~a~great~day~ahead!

-Isabelle~Williams

5 0
4 years ago
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