Answer:
B
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² = 13² + 4² = 169 + 16 = 185 ( take the square root of both sides )
x = ≈ 13.6 ( to 1 dec. place ) → B
6x
because in front of x^3 there is 6x and also the qn has asked to find the coefficient of x^3
Fill in the given values and simplify.
b
bc i just did it
