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Phoenix [80]
3 years ago
9

Please! Solve f(x)-g(x) if f(x)=1/2x^4 - x^2 and g(x)= 3/4x^4 +3x^3 - x^2

Mathematics
1 answer:
igomit [66]3 years ago
6 0

Answer:

f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}

Step-by-step explanation:

This is a subtraction between polynomials, since both functions are polynomials, hence, to solve the problem with need to perform the subtraction, by coefficients.

f(x)= \frac{1}{2}x^{4}+0x^{3}-x^{2}\\\\g(x)=\frac{3}{4}x^{4}+3x^{3}-x^{2}

By performing the subtraction, we have:

f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}

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How do you find the range of a linear graph
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Select all of the following tables which represent y as a function of x.x 5 10 11y 3 9 15x 5 10 11y 3 9 9x 5 10 10y 3 9 15
11Alexandr11 [23.1K]

Answer:

Table 1 and 2 represent a function

Step-by-step explanation:

Given

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

<em>Table 2</em>

x 5 10 11

y 3 9 9

<em>Table 3</em>

x 5 10 10

y 3 9 15

Required

Determine which of the tables represent that y is a function of x

For a relation to be a function; the x values must be unique.

In other words, each x value must not be repeated;

Having said that;

Analyzing Table 1

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

Note that the x rows are unique as no value were repeated;

Hence, Table 1 is a function

<em>Table 2</em>

x 5 10 11

y 3 9 9

Note that the x rows are unique as no value were repeated;

Hence, Table 2 is a function

<em>Table 3</em>

x 5 10 10

y 3 9 15

Note that the x rows are not unique because 10 was repeated twice;

Hence, Table 3 is not a function

7 0
3 years ago
What is the solution?
exis [7]

Answer:

no solution

Step-by-step explanation:

The lines do not cross at any point; therefore, there is no solution.

3 0
3 years ago
What is “The sum of a number of 6” as an algebraic expression. <br><br> HURRY PLEASE
lions [1.4K]

Answer:

This question makes no sense but here we go:

Step-by-step explanation:

Assuming the sum must be equal to six:

x+y = 6

Comment if i'm getting the wrong idea, this question makes like no sense to me. Perhaps a grammatical error?

3 0
2 years ago
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