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Nesterboy [21]
2 years ago
11

-10 = y/11 - 13 solve for y

Mathematics
2 answers:
Flauer [41]2 years ago
6 0

Answer:

10=y/11-13

We move all terms to the left:

-10-(y/11-13)=0

-y/11+13-10=0

We multiply all the terms by the denominator

-y+13*11-10*11=0

We add all the numbers together, and all the variables

-1y+33=0

We move all terms containing y to the left, all other terms to the right

-y=-33

y=-33/-1

y=+33

liq [111]2 years ago
6 0

Answer:

- 10 =  \frac{y}{11}  - 13

3 =  \frac{y}{11}  \\ y = 33

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2 years ago
Can someone help me on this question?
notsponge [240]

Answer:

x = 19.6

Step-by-step explanation:

By applying cosine rule in ΔBCD,

cos(30)° = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

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\frac{\sqrt{3}}{2}=\frac{BC}{16}

BC = 8\sqrt{3}

Now, by applying sine rule in ΔBAC,

sin(45)° = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{1}{\sqrt{2}}=\frac{AB}{BC}

\frac{1}{\sqrt{2}}=\frac{x}{8\sqrt{3}}

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3 0
2 years ago
Given the geometric sequence where a1 = 3 and r = √2 find a9
Zigmanuir [339]

Answer:

a_9=48

Step-by-step explanation:

we are given

sequence is geometric

so, we can use nth term formula

a_n=a_1(r)^{n-1}

we have

a_1=3

r=\sqrt{2}

we have to find a9

so, we can plug n=9

we get

a_9=3(\sqrt{2})^{9-1}

a_9=2^4\cdot \:3

a_9=48

8 0
2 years ago
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