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3 years ago

18

Mathematics

1 answer:

asambeis [7]3 years ago

7 0

Answer:

Step-by-step explanation:

When we have a horizontal translation on the x-axis, it means the translation in question would be affecting only the x component of our function

With respect to the question, what we have here is that we are going to take out some values from x (or add some values) to it

Thus;

f(x) = x^2 would be;

g(x) = (x-4)^2

Corresponding to a shift to the right of upto 4 units on the x axis

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-4(3-1)+2 simplify

sweet-ann [11.9K]

Answer:-11

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the radius of the sphere with a volume of 32/81π cubic yards. Write your answer as a fraction in simplest form.

alexdok [17]

$\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=\frac{32\pi }{81} \end{cases}\implies \cfrac{32\pi }{81}=\cfrac{4\pi r^3}{3}\implies \cfrac{96\pi }{81}=4\pi r^3 \\\\\\ \cfrac{96\pi }{324\pi }=r^3\implies \cfrac{8}{27}=r^3\implies \sqrt[3]{\cfrac{8}{27}}=r\implies \cfrac{\sqrt[3]{8}}{\sqrt[3]{27}}=r\implies \cfrac{2}{3}=r$

5 0

4 years ago

The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with a mean of

Svetach [21]

Answer:

(a) P(1000 < X < 1500) = 0.0256

(b) P(X < 1025) = 0.0392

(c) P(X > 1200) = 0.6554

(d) Percentile rank of a bag that contains 1425 chocolate chips = 90.98%

Step-by-step explanation:

We are given that the number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with a mean of 1252 chips and standard deviation 129 chips.

Firstly, Let X = number of chocolate chips in a bag

The z score probability distribution for is given by;

Z = $\frac{ X - \mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 1252 chips

$\sigma$ = standard deviation = 129 chips

(a) Probability that a randomly selected bag contains between 1000 and 1500 chocolate chips, inclusive is given by = P(1000 $\leq$ X $\leq$ 1500) = P(X $\leq$ 1500) - P(X < 1000)

P(X $\leq$ 1500) = P( $\frac{ X - \mu}{\sigma}$ $\leq$ $\frac{1500-1252}{129}$ ) = P(Z $\leq$ 1.92) = 0.9726

P(X < 1000) = P( $\frac{ X - \mu}{\sigma}$ < $\frac{1000-1252}{129}$ ) = P(Z < -1.95) = 1 - P(Z $\leq$ 1.95)

= 1 - 0.9744 = 0.0256

Therefore, P(1000 $\leq$ X $\leq$ 1500) = 0.9726 - 0.0256 = 0.947

(b) Probability that a randomly selected bag contains fewer than 1025 chocolate chips is given by = P(X < 1025)

P(X < 1025) = P( $\frac{ X - \mu}{\sigma}$ < $\frac{1025-1252}{129}$ ) = P(Z < -1.76) = 1 - P(Z $\leq$ 1.76)

= 1 - 0.9608 = 0.0392

P(X > 1025) = P( $\frac{ X - \mu}{\sigma}$ > $\frac{1200-1252}{129}$ ) = P(Z > -0.40) = P(Z < 0.40) = 0.6554

(d) <em>Percentile rank of a bag that contains 1425 chocolate chips is given by;</em>

Firstly we will calculate the z score of 1425 chocolate chips, i.e.;

Z = $\frac{1425-1252}{129}$ = 1.34

Now, we will check the area probability in z table which corresponds to this critical value of x;

The value which we get is 0.9098.

Therefore, 90.98% is the rank of bag that contains 1425 chocolate chips.

8 0

4 years ago

I'll give you more points but you have to answer all the parts to the question. I need this plsssss ty lol. Show all work too pl

alexira [117]

Answer:

a) 34mi

b) 10mi

c) 44mi

d) by Calculating the amount of miles it would take John to go to school plus the amount of miles it would take Sara to go to school. Then add the sum of the amount of miles it took for both to go to school.

Step-by-step explanation:

a) explanation:

$a^{2} +b^2=c^2$