Solution: The sample mean of sample 1 is:
![\bar{x}=\frac{4+5+2+4+3}{5}= \frac{18}{5}=3.6](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B4%2B5%2B2%2B4%2B3%7D%7B5%7D%3D%20%5Cfrac%7B18%7D%7B5%7D%3D3.6)
The sample mean of sample 2 is:
![\bar{x}=\frac{2+2+6+5+7}{5}= \frac{22}{5}=4.4](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B2%2B2%2B6%2B5%2B7%7D%7B5%7D%3D%20%5Cfrac%7B22%7D%7B5%7D%3D4.4)
The sample mean of sample 3 is:
![\bar{x}=\frac{4+6+3+4+1}{5}= \frac{18}{5}=3.6](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B4%2B6%2B3%2B4%2B1%7D%7B5%7D%3D%20%5Cfrac%7B18%7D%7B5%7D%3D3.6)
The sample mean of sample 4 is:
![\bar{x}=\frac{5+2+4+3+6}{5}= \frac{20}{5}=4](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B5%2B2%2B4%2B3%2B6%7D%7B5%7D%3D%20%5Cfrac%7B20%7D%7B5%7D%3D4)
The minimum sample mean of the four sample means is 3.6 and maximum sample mean of the four sample means is 4.4.
Therefore, using his four samples, between 3.6 and 4.4 will Ardem's actual population mean lie.
Hence the option 3.6 and 4.4 is correct
Answer:
(x+2) (x+3) (x-5)
Step-by-step explanation:
x³-19x-30 = (x+2) (x²+ax-15) ... x³=x*(1*x²) while -30= (2)*(-15)
x³ +<u> 0</u>*x² - 19x -30 = x³ + (<u>2+a</u>)x² + (2a-15)x -30
2+a = 0
a = -2
x³-19x-30 = (x+2) (x²-2x-15) = (x+2) (x+3) (x-5)
Since the midpoint lies on the axis, both ends are therefore equidistant from the axis and are mirrors of each other so..
Q = (4,9)
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