Question

Given P(E or F) = 0.16, P(E) = 0.12, and P(F) = 0.17, what is P(E and F)?

Answer 1

$P(E \cap F)=P(E)+P(F)-P(E \cup F)\\\\ P(E \cap F)=0.16+0.12-0.17=0.11$