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3 years ago

Given P(E or F) = 0.16, P(E) = 0.12, and P(F) = 0.17, what is P(E and F)?

Mathematics

1 answer:

DiKsa [7]3 years ago

6 0

$P(E \cap F)=P(E)+P(F)-P(E \cup F)\\\\ P(E \cap F)=0.16+0.12-0.17=0.11$

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