Question

Plz help !! Needed to graduate

Answer 1

Answer:   $\bold{\dfrac{2\pm \sqrt{36}}{16}}$

Step-by-step explanation:

$8x^2-2x-1=0\quad \rightarrow \quad a=8,\ b=-2,\ c=-1\\\\\\Quadratic\ formula: x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-2)\pm \sqrt{(-2)^2-4(8)(-1)}}{2(8)}\\\\\\.\ =\dfrac{2\pm \sqrt{4+32}}{16}\\\\\\.\ =\dfrac{2\pm \sqrt{36}}{16}$

Answer 2

Answer:

the second one

Step-by-step explanation:

Just put the equation in the quadratic formula but first get it in the ax^2+bx+c=0 form for that take 1 to the other side and subtract it

$8x^2-2x-1\\a=8,b=-2,c=-1$

the quadratic formula is shown in the picture along with the rest of the working

the answer is the second option :)

hope this helps, best of luck graduating :)