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allsm [11]
3 years ago
10

HELP ASAP PLZ!!!! Answer the fraction question in the picture below. Seth can read 6 3/4 books in 2 1/4 weeks. How many weeks ca

n seth read in 1 week?
Mathematics
1 answer:
OLga [1]3 years ago
5 0
(6 3/4 books)/(2 1/4 weeks) = (27/4 books)/(9/4 weeks)
.. = (27/9 books/week)
.. = 3 books/week
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Which of the following values are solutions to the inequality 3-2x <-10
DIA [1.3K]

Answer:

x>\frac{13}{2}

Step-by-step explanation:

3-2x \frac{13}{2}\\\\Simplify\\x>\frac{13}{2}

5 0
3 years ago
The painted area of a rectangular canvas is 72 square inches and there is a 4 inch unpainted border on all sides. The dimensions
umka21 [38]

Painted Area: 72 in^2

Unpainted Border on all sides: ====> 4 in"

4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 = 72



Answer: =====> 66 inches



My Internet kept messing up on me here, but the Answer is 66 inches, Sorry I couldn't finish working out the problem, going to check out my internet. - Thanks - P.




Hope that helps!!!! : )

7 0
4 years ago
The value of the nth term in a sequence of numbers is given by the expression 2n - 3. What is the 8th term in the sequence?
tino4ka555 [31]
C. 13 is the answer
4 0
3 years ago
I subtract 3 from a certain number, multiply the result by 5 and then add 9 if the final result is 54. find the original number
Sergeu [11.5K]

(x-3)\cdot 5+9=54\\5x-15=45\\5x=60\\x=12

8 0
2 years ago
Which of the following graphs shows the solution set for the inequality below? 3|x + 1| < 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
3 years ago
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