Complete question :
The 100m dah times in the girl's track meet were normally distributed with a mean of 13 seconds and a standard deviation of 0.3 seconds.
Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?
Answer:
21 runners
Step-by-step explanation:
Mean, μ = 13 seconds
Standard deviation, σ = 0.3
Lana's race time = 13.2
We find the proportion of runners who had race time above 13.2 ;
Proportion of who had race tune above 13.2
P(x > 13.2)
Obtain the Zscore
Zscore = (x - μ) / σ
Z = (13.2 - 13) / 0.3
Zscore = 0.2 / 0.3 = 0.6667
P(Z > 0.6667) = 0.25239 (Z probability calculator)
This is about 0.25239 * 100 = 25.24% = 25% (nearest percent)
Hence, Number of runners Lana beat = 25% of total runners ;
0.25 * 84 = 21
Hence, Lana beat about 21 runners
If m ACD = 30 => m DCB = 60.
In triangle ACD:
AC^{2}+CB^{2}=AB^{2} => AB=
=32.
=> P=16+32+
=48 +
.
Answer:
<u>160 ounces</u>
Step-by-step explanation:
A pound = 16 ounces
16x10=160 ounces
Answer: Correlation
Step-by-step explanation:
The statistics that should be used to determine if scores on these two surveys are related to each other is referred to as correlation.
Correlation indicates the degree by which the variables that are given are linearly related. Correlation is used in the testing and determination of the strength of association that can be found between two variables.
In this case, since the student wants to determine if degree of introversion or extroversion s associated satisfaction with life, the correlation will be appropriate to use.
Answer:
8125, im pretty sure this is right
Step-by-step explanation:
