The congruence theorem that can be used is: B. ASA
<h3>What is the ASA Congruence Theorem?</h3>
If we have two triangles that have two pairs of corresponding congruent angles (e.g. ∠LGH ≅ ∠HKJ and ∠LHG ≅ ∠KHJ), and a pair of corresponding congruent sides (e.g. GH ≅ HK), the triangles are said to be congruent triangles by the ASA congruence theorem.
Therefore, triangles GHL and KHL in the image given are congruent triangles by the ASA congruence theorem.
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Mean is the average of all numbers
(5+2+7+8+2+5+3)/7
Mean is 4.57
Median is the middle score so we have to arrange all the numbers from lowest to highest
2, 2, 3, 5, 5, 7, 8
Median is 5
Answer is
<span>C) y = -2x + 3 </span>
when x = 0, y = 3
when x = 1, y = -2(1) + 3 = -2 + 3 = 1
when x = 2, y = -2(2) + 3 = -4 + 3 = -1
solutions matched the table above
Based on the calculations, the coordinates of the mid-point of BC are (1, 4).
<h3>How to determine coordinates of the mid-point of BC?</h3>
First of all, we would determine the initial y-coordinate by substituting the value of x into the equation of line that is given:
At the origin x₁ = 0, we have:
y = 2x + 1
y₁ = 2(0) + 1
y₁ = 2 + 1
y₁ = 3.
When x₂ = 2, we have:
y = 2x + 1
y₂ = 2(2) + 1
y₂ = 4 + 1
y₂ = 5.
In order to determine the midpoint of a line segment with two (2) coordinates or endpoints, we would add each point together and divide by two (2).
Midpoint on x-coordinate is given by:
Midpoint = (x₁ + x₂)/2
Midpoint = (0 + 2)/2
Midpoint = 2/2
Midpoint = 1.
Midpoint on y-coordinate is given by:
Midpoint = (y₁ + y₂)/2
Midpoint = (3 + 5)/2
Midpoint = 8/2
Midpoint = 4.
Therefore, the coordinates of the mid-point of BC are (1, 4).
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Answer:
THEY START AT A DIFFERENT PLase sorry about all caps
Step-by-step explanation:
