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Brut [27]
2 years ago
11

1 more than twice as many CDs is 17

Mathematics
1 answer:
Zinaida [17]2 years ago
3 0

Answer:

original number is 8

Step-by-step explanation:

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A recipe for a cake calls for 6 cups of flour Michelangelo’s has already put in 2 cups how many more cups does she need to put i
il63 [147K]

Ummm...4?

Am I stupid or something, that is a simple subtraction problem right? 6-2=4?

I am so confused, but okay.

Your answer is 4 cups.

4 0
2 years ago
Can someone explain how you solve proofs?
kap26 [50]

Answer:

Yeahh

Step-by-step explanation:

Write the statement in one side and give the reasons on other side.

And then proof it by accurate reason

6 0
3 years ago
Find the value of x.<br><br> log 2 x = 3<br><br> A. 5<br><br> B. 6<br><br> C. 8<br><br> D. 9
Nataly_w [17]

Answer: Option C

x =8

Step-by-step explanation:

To solve this problem use the properties of the logarithms.

We know that the inverse function of y = log_2 (x) is y = 2 ^ x.

So when composing the function with its inverse function we have to:

2 ^ {log_2 (x)} = x.

Now apply this property on both sides of the equation

log_2(x) = 3\\\\2^{log_2(x)}=2^3\\\\x = 2^3\\\\x = 8

the answer is the option C

4 0
3 years ago
Read 2 more answers
Select all of the following that are quadratic equations.
kifflom [539]
A quadratic equation is one in which the highest exponent of x is 2.
7x^2+14x=0 is quadratic; the highest exponent is 2.
x³-3x²+1=0 is NOT quadratic.  The highest exponent of x is 3, not 2.
5x-7=0 is NOT quadratic.  The highest exponent of x is 1, not 2.
x²+3x-5=0 is quadratic; the highest exponent of x is 2.
x-5=9x+7 is NOT quadratic.  The highest exponent of x is 1, not 2.
x²-x=3x+7 is quadratic; the highest exponent of x is 2.
5 0
3 years ago
An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
Papessa [141]

Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

g = Force of gravity,

v_0 = Initial velocity,

h_0 = Initial height.

For our given scenario g=-9.8, v_0=49 and h_0=58.8. Upon substituting these values in object's height function, we will get:

s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

6 0
3 years ago
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