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Sonja [21]
4 years ago
11

Use complete sentences to describe the transformation that maps ABCD onto its image.

Mathematics
1 answer:
Lapatulllka [165]4 years ago
6 0

General Idea:

When a point or figure on a coordinate plane is moved by sliding it to the right or left or up or down, the movement is called a translation.

Say a point P(x, y) moves up or down ' k ' units, then we can represent that transformation by adding or subtracting respectively 'k' unit to the y-coordinate of the point P.

In the same way if P(x, y) moves right or left ' h ' units, then we can represent that transformation by adding or subtracting respectively 'h' units to the x-coordinate.

P(x, y) becomes P'(x\pm h, y\pm k). We need to use ' + ' sign for 'up' or 'right' translation and use ' - ' sign for ' down' or 'left' translation.

Applying the concept:

The point A of Pre-image is (0, 0). And the point A' of image after translation is (5, 2). We can notice that all the points from the pre-image moves 'UP' 2 units and 'RIGHT' 5 units.

Conclusion:

The transformation that maps ABCD onto its image is translation given by (x + 5, y + 2),

In other words, we can say ABCD is translated 5 units RIGHT and 2 units UP to get to A'B'C'D'.

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Morgarella [4.7K]
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lina2011 [118]

Answer:

\displaystyle \boxed{\frac{60}{61}} = cos\:θ_1

Step-by-step explanation:

\displaystyle arcsin\: \frac{11}{61} ≈ 0,1813197744 \\ \\ cos\:0,1813197744 ≈ \frac{60}{61}

Since this answer is in <em>Quadrant</em><em> </em><em>I</em>,<em> </em>this would be a positive-positive answer, which in this case, will remain a positive.

<u>Extended</u><u> </u><u>Information</u><u> </u><u>on</u><u> </u><u>Quadrants</u>

\displaystyle Positive-Negative → Quadrant\:IIII \\ Negative-Negative → Quadrant\:III \\ Negative-Positive → Quadrant\:II \\ Positive-Positive → Quadrant\:I \\ \\

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\displaystyle y-values → sin\:θ \\ x-values → cos\:θ

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