Answer:
∠ABC ≅ ∠XYZ
Step-by-step explanation:
Given: ΔABC is similar to ΔXYZ.
If two triangles are similar, then
1. the corresponding angles are congruent
2. the corresponding sides are proportional
From the options given,
AB ≅ XY is not applicable for similar triangles. Hence the option is wrong.
∠ABC ≅ ∠XYZ since ΔABC ≅ ΔXYZ
Hence the answer is ∠ABC ≅ ∠XYZ
Answer: -8 and 9
Explanation: -8 x 9 = -72 and -8 + 9 = 1
Answer:

Step-by-step explanation:
Consider irght triangle PRS. By the Pythagorean theorem,

Thus,

Consider isosceles triangle MSC. In this triangle

The area of this triangle is

Consider right triangle PTS. The area of this triangle is

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A= bh(1/2)
a=12(14)(1/2)
a= 168(1/2)
a= 84inches
Answer:
what do you need here there has to be something to do here your just giving me a variable
Step-by-step explanation: