Answer:
The value of x is 3
Step-by-step explanation:
∵ Quadrilateral ABCD is congruent to quadrilateral JKLM
∴ AB = JK and BC = KL
∴ CD = LM and AD = JM
∵ BC = 8x + 7
∵ KL = 31
∵ BC = KL
→ Equate their right sides
∴ 8x + 7 = 31
→ Subtract 7 from both sides
∵ 8x + 7 - 7 = 31 - 7
∴ 8x = 24
→ Divide both sides by 8 to find x
∴ =
∴ x = 3
∴ The value of x is 3
|x| = x for x ≥ 0
examples:
|3| = 3; |0.56| = 0.56; |102| = 102
|x| = -x for x < 0
examples:
|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102
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Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
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Put the values of x to the equation of the function h(x):
Answer:
-6x^6y^5
Step-by-step explanation:
you have to find p such that
(-3y)(p) = 18
So just divide to find p
p = = -6