(For question 1 you have to do it yourself, get a ruler and measure the actual length of the drawing, then multiply it by 8 to get the actual dimensions in the exercise. )
Example, if you measure 4 inches, the actual dimension will be 4 x 8 = 32 ft
2. (Scale drawing 1:5 is that every 1 (length units) will be equal to 5(length units) in the actual dimensions)
Model : 3ft ; 7m
Actual : 15ft ; 35m (corresponding)
Actual : 20yd ; 12.5 cm
Model : 4yd ; 2.5 cm
6. 1.5 ft = 1.5 x 12 = 18 inches.
The model is 3 inches, and the actual rose is 18 inches -> The scale of the drawing is 6. (enlargement)
Same goes to the scale factor, but this time is the quotient of the corresponding side -> 3 : 18 = 1:6.
(If I got any parts wrong just tell me, I actually kinda forgot these kind of stuff)
Solution:
The standard equation of a hyperbola is expressed as
Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.
Thus, the equation will be expressed in the form:
The asymptote of n hyperbola is expressed as
Given that the asymptotes are
This implies that
To evaluate the value of h and k,
Answer : 3r+5 hope this helps!
B is the answer and why is bc I took the quiz
Answer:
A . 60
Step-by-step explanation:
30 x 2 = 60
