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3 years ago

6

2x + 3(x + 5) = 5(x – 3) why is it a no solution answer 50 POINT!!!!!!!!!!!

2 answers:

Nesterboy [21]3 years ago

6 0

2x +3x + 25 = 5x - 15
5x + 25 = 5x - 15
5x - 5x = -15 - 25
0 ≠ -35

melomori [17]3 years ago

3 0

Answer: no solution

Why?: because when a problem has no solution you'll end up with a statement that's false. For example: 0=1 This is false because we know zero can't equal one. ... So, we say this problem has no solution. This means no matter what number you put in for the variable x, you will never get anything that equals one another. hope it helps!

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HELPPPPPPPPPPPP (-12)^3:8^3

Nadusha1986 [10]

Answer:

-1728:512

Step-by-step explanation:

(-12)³ = -1728

8³ = 512

ratio is -1728:512

8 0

2 years ago

✓<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B19%20%2B%20%20%5Csqrt%7B30%20%2B%20%20%5Csqrt%7B32%20%2B%20x%20%20%7D%20%7D%

Setler79 [48]

We'll have to repeatedly square both sides of the equation, in order to get rid of the square roots. Squaring a first time yields

$19+\sqrt{30+\sqrt{32+x}}=25$

Move the 19 to the right hand side:

$\sqrt{30+\sqrt{32+x}}=6$

And square again:

$30+\sqrt{32+x}=36 \iff \sqrt{32+x}=6$

Square one last time:

$32+x=36 \iff x=36-32=4$

Let's check the solutions: all these squaring might have created external solutions:

$\sqrt{19+\sqrt{30+\sqrt{32+4}}}=\sqrt{19+\sqrt{30+6}}=\sqrt{19+6}=\sqrt{25}=5$

So, $x=4$ is a feasible solution.

8 0

3 years ago

Order each set of integers from least to greatest (15, 17, 21, 6,3)

Natasha2012 [34]

Answer:

3, 6, 15, 17, 21.

Step-by-step explanation:

Brainliest?

3 0

3 years ago

Mathematical induction of 3k-1 ≥ 4k ( 3k = k power of 3 )

tresset_1 [31]

For making mathematical induction, we need:

a base case

An $n_0$ for which the relation holds true

the induction step

if its true for $n_i$ , then, is true for $n_{i+1}$

<h3>base case</h3>

the relationship is not true for 1 or 2

$1^3-1 = 0 < 4*1$

$2^3-1 = 8 -1 = 7 < 4*2 = 8$

but, is true for 3

$3^3-1 = 27 -1 = 26 > 4*3 = 12$

<h3>induction step</h3>

lets say that the relationship is true for n, this is

$n^3 -1 \ge 4 n$

lets add 4 on each side, this is

$n^3 -1 + 4 \ge 4 n + 4$

$n^3 + 3 \ge 4 (n + 1)$

now

$(n+1)^3 = n^3 +3 n^2 + 3 n + 1$

$(n+1)^3 \ge n^3 + 3 n$

if $n \ge 1$ then $3 n \ge 3$ , so

$(n+1)^3 \ge n^3 + 3 n \ge n^3 + 3$

$(n+1)^3 \ge n^3 + 3 \ge 4 (n + 1)$

$(n+1)^3 \ge 4 (n + 1)$

and this is what we were looking for!

So, for any natural equal or greater than 3, the relationship is true.

4 0

3 years ago

Find the value of y that makes the equation y = -x + 5 true, when x = -4.

bogdanovich [222]

The answer is c,i believe

4 0

3 years ago

Read 2 more answers