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ivanzaharov [21]
3 years ago
6

How many times does the graph of the function below intersect or touch the x-axis y=-2x^2+3x+5

Mathematics
2 answers:
Effectus [21]3 years ago
6 0

Answer:

twice

Step-by-step explanation:

joja [24]3 years ago
5 0

Answer:

The function intersect the x-axis two times

Step-by-step explanation:

we have

y=-2x^{2}+3x+5

To find the x-intercepts equate the equation to zero

so

0=-2x^{2}+3x+5

-2x^{2}+3x+5=0

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-2x^{2}+3x+5=0  

so

a=-2\\b=3\\c=5

substitute in the formula

x=\frac{-3(+/-)\sqrt{3^{2}-4(-2)(5)}} {2(-2)}

x=\frac{-3(+/-)\sqrt{49}} {-4}

x=\frac{-3(+/-)7} {-4}

x1=\frac{-3(+)7} {-4}=-1

x2=\frac{-3(-)7} {-4}=2.5

so

The function has two x-intercepts

therefore

The function intersect the x-axis two times

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Which of these represents the equation of a line that passes through the points (-5, -4) and (3, 8)?
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Function F(x)=x+1 and g(x)=5x+1 find the f(4)=g(x+1)
Lapatulllka [165]

The function of f(4) = g(x+1) gives the value of x that is -1/5.

<h3>What is the function addition?</h3>

It is the addition of two functions similar to the addition of any two polynomial functions.

Given;

F(x)=x+1

g(x)=5x+1

We need to find f(4)=g(x+1)

First substitute x = 4 in f(x)

F(x)=x+1

F(4) = 4 + 1

F(4) =  5

Now substitute x = x + 1 in g(x)

g(x)=5x+1

g(x + 1) = 5(x + 1) + 1

g(x + 1) = 5(x + 1) + 1

g(x + 1) = 5x + 5 + 1

g(x + 1) = 5x + 6

Then ,

F(4) = g(x + 1)

5 = 5x + 6

5x = 5 - 6

5x = -1

x = -1/5.

The function of f(4) = g(x+1) gives the value of x that is -1/5.

Learn more about function;

brainly.com/question/14438192

#SPJ1

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2 years ago
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Airida [17]

Answer:

2x⁴ - 20x² - 78

To factor the expression look for the LCM of the numbers

LCM of the numbers is 2

Factorize that one out

That's

2( x⁴ - 10x² - 39)

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