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guapka [62]
3 years ago
12

Which relations are functions? Select function or not a function for each graph

Mathematics
1 answer:
katovenus [111]3 years ago
7 0
This is NOT a function. The reason why is because we are able to pass a single vertical line through more than one point on the cure. It fails the vertical line test.

For it to be a function, every input x must lead to exactly one output y
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Which expressions are polynomials?
igor_vitrenko [27]

Option A: z + 1

Option B: 6 + w

Option D: 2 x^{4}-y

Solution:

Let us first define the polynomial.

A polynomial can have constants, variables, exponents and fractional coefficients.

A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.

<u>To find which expressions are polynomial:</u>

Option A: z + 1

By the definition, z + 1 is a polynomial.

It is polynomial.

Option B: 6 + w

By the definition, 6 + w is a polynomial.

It is polynomial.

Option C: y^{2}-\sqrt[3]{y}+4

y^{2}-\sqrt[3]{y}+4=y^{2}-{y}^{1/3}+4

Here, y have fractional exponent.

So, it is not a polynomial.

Option D: 2 x^{4}-y

By the definition, 2 x^{4}-y is a polynomial.

It is polynomial.

Hence z + 1, 6 +w and 2 x^{4}-y are polynomials.

6 0
3 years ago
A store sells two brands of hand lotion. Brand X costs $3.25 for 5 fluid ounces.
olga_2 [115]

Answer:

\frac{3,25}{5}=0,65 \\ for brand x for 1 fluid ounces

\frac{6}{8}=0,75 for brand y

0,75-0,65=0,1

Brand x costs $0,1 less

Step-by-step explanation:

3 0
3 years ago
Find the slope/rate of change of the line on the graph.
ohaa [14]

Answer:

y=-1

From where the line crosses the y axis, it goes up 1 and over 1 from each plane although its moving to the left from 0 every time. This means the slope is negative.

In the equation y=mx+b, b is the y intercept and m is the slope

plugin the info and you get y=-1x+0 or

y=-1x

Step-by-step explanation:

5 0
2 years ago
Write an equation in slope-intercept form of the line.
alexira [117]

Answer:

y=x-3

Step-by-step explanation:

To find slope, use m=y2-y1/x2-x1, using values of x and y from two different points. Once you have found slope, take another point and use the point-slope equation y-y1=m(x-x1) and substitute in slope for m and the point for x1 and y1. Isolate y by subtracting y1 from both sides.

3 0
2 years ago
I don’t kno the answer help
PolarNik [594]

Answer:

Yes

Step-by-step explanation:

It is true because the equation would be 1 is less than or equal to 3-(-4)

4 0
2 years ago
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