Answer:
Step-by-step explanation:
Reduction to normal from using lambda-reduction:
The given lambda - calculus terms is, (λf. λx. f (f x)) (λy. Y * 3) 2
For the term, (λy. Y * 3) 2, we can substitute the value to the function.
Therefore, applying beta- reduction on "(λy. Y * 3) 2" will return 2*3= 6
So the term becomes,(λf. λx. f (f x)) 6
The first term, (λf. λx. f (f x)) takes a function and an argument, and substitute the argument in the function.
Here it is given that it is possible to substitute the resulting multiplication in the result.
Therefore by applying next level beta - reduction, the term becomes f(f(f(6)) (f x)) which is in normal form.
75 additional minutes were used
$61.20-$49.95=$11.25
$11.25/$0.15=75 additional minutes
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5
8
5
hopefully its right i'm not good at this kind of stiff
Answer: Linear
Step-by-step explanation: A linear function can have different rates of change over different intervals.
(I don't know if this is correct, but this is my understanding of it.)
