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Elis [28]
3 years ago
9

How do you solve (-1) ^2

Mathematics
2 answers:
likoan [24]3 years ago
4 0

(-1)^2

-negative and -negative= + positive

-1*-1 - two times ( because of the exponent)

=1

Answer: 1

BabaBlast [244]3 years ago
3 0

Answer:

1

Step-by-step explanation:

You multiply -1 x -1 because it's squared and the negatives cancel out and 1 times 1 is 1

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Please help! 45 points !!
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<u>Answer:</u>

A. 8.2 x 10^6

<u>Step-by-step explanation:</u>

To get what 4.1x10^3 is equal to you move the decimal point to the right three times. This leaves you with 4,100. To get what 2.0x10^3 is equal to, you move the decimal point to the right three times. This leaves you with 2,000. 4,100 x 2,000 is 8,200,000. Then move the decimal to the left until it is behind the 8. In order to do this, you would have to move the decimal point 6 times. So the final answer is 8.2 x 10^6.

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The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.
Dovator [93]

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

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So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

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When the british system of units was first developed, what was the most common object used as a basis for measuring length?
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