How do you solve (-1) ^2
2 answers:
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We can start by finding the gradient of LM
Two perpendicular lines will meet the requirement
×
=-1
Two parallel lines have equal gradients
NM is perpendicular to LM, hence the gradient of NM is -1
KN is a line that is parallel to NM, hence the gradient is 1
KL is perpendicular to LM, hence the gradient of KL is -1
Two perpendicular lines will meet the requirement
Two parallel lines have equal gradients
NM is perpendicular to LM, hence the gradient of NM is -1
KN is a line that is parallel to NM, hence the gradient is 1
KL is perpendicular to LM, hence the gradient of KL is -1
Answer:
Possible locker numbers for Selma are: 3, 5 and 29
Step-by-step explanation:
First of all, let us have a look at the definition of a prime number.
A <em>prime number</em> is a number which is divisible either by 1 or the number itself.
No other number divides the prime number other than 1 and the number itself.
Now, let us factorize the given number 435 and let us observe the what all possibilities are there.
Factorizing 145 further:
No further factors are possible.
Therefore 3, 5 and 29 are the prime factors of 435.
So, the answer is:
Possible locker numbers for Selma are: 3, 5 and 29