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Elis [28]
3 years ago
9

How do you solve (-1) ^2

Mathematics
2 answers:
likoan [24]3 years ago
4 0

(-1)^2

-negative and -negative= + positive

-1*-1 - two times ( because of the exponent)

=1

Answer: 1

BabaBlast [244]3 years ago
3 0

Answer:

1

Step-by-step explanation:

You multiply -1 x -1 because it's squared and the negatives cancel out and 1 times 1 is 1

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Given that <span>DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence A</span><span>G, BG, and CG are equal.

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3 0
3 years ago
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OLEGan [10]

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Please Help!!!! 20 Points!!!!
Mekhanik [1.2K]

Answer:

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