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3 years ago

5

A commercial jet liner hits an air pocket and drops 223 feet. After climbing 177 feet it drops another 162 feet. What is its ove

rall vertical change?
The jets overall vertical change is
?? feet

1 answer:

kondaur [170]3 years ago

4 0

218 is the overall vertical change

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Solve this equation by using the look inside method to rewrite the problem <br><br> -81 = 3(5 - 4r)

TEA [102]

－81＝3(5－4r)
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－4r＝－5－27
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Leon measured the distance each of his four toy cars rolled across the floor. Which car measurement that has a 4 in the thousand

Kobotan [32]

0.714 and so does 0.224 has 4 in the thousandths place, but in shortest distance I believe it is 0.714

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The functions f(x) and g(x) are described below:

sesenic [268]

Suppose that the <u>function</u> f(x) is the <u>parrent</u> function and the<u> graph</u> of the function g(x)=f(x)-a can be obtained from the graph of the parrent function f(x) by <u>shifting down</u> a units.

Rewrite the expression for the function $g(x)$ in the following way:

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3 years ago

Read 2 more answers

Please help me ASAP. This is for Trigonometry, Math

Rufina [12.5K]

Answer: C) exactly one triangle

<u>Step-by-step explanation:</u>

Given: ∠A = 45°, ∠B = 65°, side c = 4 cm

By the Triangle Sum Theorem, ∠C = 70°

Now you have a proportion so you can use the Law of Sines to find the exact length of side a and of side b.

$\dfrac{\sin\angle A}{a}=\dfrac{\sin\angle B}{b}=\dfrac{\sin\angle C}{c}\\\\\\\dfrac{\sin 45^o}{a}=\dfrac{\sin65^o}{b}=\dfrac{\sin70^o}{4}$

Thus, there is exactly one triangle.

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3 years ago

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3$

$|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

3 0

3 years ago