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3 years ago

Calculate the Highest common factor of 130,260,390

Mathematics

2 answers:

kirza4 [7]3 years ago

6 0

Answer:

130

Step-by-step explanation:

130 = 2x5x13

260 = 2x2x5x13

390 = 2x3x5x13

common factors = 2, 5, 13

therefore, 2x5x13 = 130

Cheers!

qwelly [4]3 years ago

4 0

the Highest common factor of 130,260,390 = 130

130 = 2⋅5⋅13

260 = 2⋅2⋅5⋅13

390 = 2⋅3⋅5⋅13

Common multipliers (130; 260; 390): 2, 5, 13

Now to find the highest Common factor you need to multiply the common factors

Answer: (130 ; 260 ; 390) = 2 ∙ 5 ∙ 13 = 130

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3 years ago

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3 years ago

A company sells each product they make for $84.00. They pay $2,100.00 in monthly costs such as rent and bills as well as $70.00

mel-nik [20]

Answer:

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Step-by-step explanation:

<em>Since equations are not listed, i will simply figure out the correct answer.</em>

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Profit is Income MINUS Cost.

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Also a variable cost of 70 per unit (x), if x units sold, then variable cost would be "70x"

Total Cost = 2100 + 70x

Now, the income is from sales of each unit. Each unit sells for $84 and if x units sold, company's income would be:

84x

So, profit will be:

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We can write the equation as:

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6 0

3 years ago

Let f (x)=1/x and g (x)=x^2+5x. A. Find (f×g)(x). B. Find the domain and range of (f×g)(x).

Ira Lisetskai [31]

we are given

$f(x)=\frac{1}{x}$

$g(x)=x^2+5x$

(A)

(f×g)(x)=f(x)*g(x)

now, we can plug it

$(fXg)(x)=\frac{1}{x} (x^2+5x)$

we can simplify it

$(fXg)(x)=\frac{1}{x} (x(x+5))$

$(fXg)(x)=x+5$

(B)

Domain:

Firstly, we will find domain of f(x) , g(x) and (fxg)(x)

and then we can find common domain

Domain of f(x):

$f(x)=\frac{1}{x}$

we know that f(x) is undefined at x=0

so, domain will be

$(-\infty,0)$ ∪ $(0,\infty)$

Domain of g(x):

$g(x)=x^2+5x$

Since, it is polynomial

so, it is defined for all real values of x

now, we can find common domain

so, domain will be

$(-\infty,0)$ ∪ $(0,\infty)$ ..............Answer

Range:

Firstly, we will find range of f(x) , g(x) and (fxg)(x)

and then we can find common range

Range of f(x):

$f(x)=\frac{1}{x}$

we know that range is all possible values of y for which x is defined

since, horizontal asymptote will be at y=0

so, range is

$(-\infty,0)$ ∪ $(0,\infty)$

Range of g(x):

$g(x)=x^2+5x$

Since, it is quadratic equation

so, its range will be

$[-6.25,\infty)$

now, we can find common range

so, range will be

$(-6.25,0)$ ∪ $(0,\infty)$ .............Answer

6 0

3 years ago

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bearhunter [10]

Answer:

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So here m = 4/4 = 1 and c = 6, so it's:

y = 1x + 6.

3 0

3 years ago

Calculate the Highest common factor of 130,260,390​

Calculate the Highest common factor of 130,260,390