Question

The speed of a moving sidewalk at an airport is 6 ft/sec. a person can walk 51 ft forward on the moving sidewalk in the same time it takes to walk 7 ft on a nonmoving sidewalk in the opposite direction. At what rate wools a person walk on a moving sidewalk?

Answer 1

Distance = rate*time
Let v be speed of person walking.

6t + vt = 51
vt = 7

Solve for t:
6t + 7 = 51
t = 44/6 = 22/3

Sub in to find v:
v(22/3) = 7
v = 21/22

The speed a person walks is 21/22 ft/sec