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My name is Ann [436]
3 years ago
10

24. Which term refers to cells having different jobs in an organism?

Biology
1 answer:
lyudmila [28]3 years ago
4 0

Answer:

it means it is multicellular.

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A solution of acetic acid is prepared in water by adding 11.1 g of sodium acetate to a volumetric flask and brining in the volum
velikii [3]

Answer:

The concentration of

the Acetic Acid is 0.0325M

the Sodium Acetate is 0.1028M

Explanation:

Given

The dissociation of acetic acid is

CH3COOH + CH3COO- + H+ + HA -> A- + H+

We calculate the molarity of sodium acetate by using

Molarity = Moles/Volume

The formula weight of sodium acetate is 82.03 g/mol.

Moles = 11.1g/82.03g/mol

= 0.1353M

Since the volume is 1L, the molarity of sodium acetate will still be 0.1353M

The starting concentration of sodium acetate is 0.1353M

The final concentration of sodium acetate is the starting amount of sodium acetate, minus the amount that was protonated.

Assume that, x = concentration of acetic acid, which is the amount of sodium acetate that was protonated.

From the Henderson-Hasselbalch equation

PH = pKa + log[A-]/[HA]

[A-] = 0.1353 - x

[HA] = x

pKa = 4.75

PH = 5.25

Substitute in these values

5.25 = 4.75 + log(0.1353-x)/x

log(0.1353 - x)/x = 5.25 - 4.75

log(0.1353-x)/x = 0.5

log(0.1353 - x)/x = ½

(0.1353-x)/x = 10^½

(0.1353 - x)/x = 3.1623

0.1353 - x = 3.1623x

0.1353 = x + 3.1623x

0.1353 = 4.1623x

x = 0.1353/4.1623

x = 0.0325M

Therefore [HA] = x = 0.0325M

[A-] = 0.1353 - x = 0.1353 - 0.0325 =

[A-] = 0.1028M

8 0
3 years ago
Some inbred strains of the weedy plant Arabidopsis thaliana flower early in the growing season, but other strains flower at late
RoseWind [281]

Answer:

a. Let us consider that L is responsible for late and l is responsible for early. From the mentioned data, it can be concluded that allele L or late is dominant over early. By crossing plants 1 and 4 we get the expected ratio of 3: 1, which shows that it follows Mendel's law of dominant.  

b. The genotype of all the four plants are:  

1st plant = Ll

2nd plant = ll

3rd plant = LL

4th plant = Ll

c. If the plant 1 is self-fertilized then the expected progeny will be 3 (late): 1 (early).  

In case if the 2nd plant is self-fertilized, the expected progeny will be only early.  

In case if the 3rd plant is self-fertilized, the expected progeny will be only late.  

In case if the 4th plant is self-fertilized, the expected progeny will be 3 (late): 1 (early).  

3 0
3 years ago
What are the products of photosynthesis? .-.
sukhopar [10]

Answer:

products of photosynthesis are glucose and oxygen

5 0
3 years ago
I NEED HELP THIS IS DUE IN AN HOUR !!<br> i’ll give u brainliest !
Hatshy [7]

Answer:

A. Compound Is the answer

Explanation:

3 0
2 years ago
Read 2 more answers
Plz help i'll give you brainliest if its right
11Alexandr11 [23.1K]
No se que es esto no hablo inglés
8 0
3 years ago
Read 2 more answers
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