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NNADVOKAT [17]
4 years ago
6

Is 7.52 a rational number?

Mathematics
1 answer:
Elena L [17]4 years ago
7 0

Answer:

It's a decimal number......

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Question 5 (1 point)
aleksley [76]

Answer:

A = x^2 + 5x - 14

Step-by-step explanation:

A = L × W

A = (x+7) × (x-2)

A = x^2 + 7x - 2x - 14

5 0
4 years ago
4 x 105 in standard notation
Paul [167]

Answer:

Lol its 420

Step-by-step explanation:

6 0
3 years ago
At a school carnival, 6 out of 60 tickets sold were early-admission tickets. What percentage of the tickets were early-admission
professor190 [17]

Answer:10 percent

Step-by-step explanation:

4 0
3 years ago
Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:
kondaur [170]
\text{Proof by induction:}
\text{Test that the statement holds or n = 1}

LHS = (3 - 2)^{2} = 1
RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS
\text{Thus, the statement holds for the base case.}

\text{Assume the statement holds for some arbitrary term, n= k}
1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}

\text{Prove it is true for n = k + 1}
RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}

LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}
= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}
= \frac{k(6k^{2} + 15k + 11) + 2}{}
= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}
= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}
= RHS

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.
3 0
4 years ago
Stephen kicked a ball inside. The equation that represents the height h in feet of the ball after being kicked and elapsed amoun
kodGreya [7K]

Answer:

The maximum height of the ball is: 14.0625ft

Step-by-step explanation:

The missing information is:

h(t) = 30t - 16t^2

Required

The maximum height the ball attained

First, we calculate the time to reach the maximum height.

For a function: h(t) = at^2 + bt + c

The maximum is: t = \frac{-b}{2a}

So, the maximum of h(t) = 30t - 16t^2 is:

t = \frac{-b}{2a}

Where

a = -16; b = 30

So:

t = -\frac{30}{2*-16}

t = -\frac{30}{-32}

t = \frac{30}{32}

t = 0.9375

The maximum height is then calculated as:

h(t) = 30t - 16t^2

h(0.9375) = 30 * 0.9375- 16 * 0.9375^2

h(0.9375) = 28.125- 14.0625

h(0.9375) = 14.0625

8 0
3 years ago
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