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trasher [3.6K]
3 years ago
10

L and ben are drivers for sd trucking company. one snowy day, ben left sd at 8:00

Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0

Alright, lets get started.

Ben left at 8:00 AM and Al left at 11:00 AM.

Suppose dispatcher retrieves data after t hrs when Al left SD.

We know the average speed of Al = 40 miles per hr

So, distance covered by Al = Time * speed

Distance covered by Al = 40 t

We know average speed of Ben = 20 miles per hr

As we know Ben left SD 3 hrs before, time taken by Ben will be 3 hrs higher than AL means (t+3)

So distance covered by Ben = 20 (t + 3)

Total distance covered by both will be = 40 t + 20 (t+3)

Total distance covered by both will be = 40 t + 20 t + 60

Total distance covered by both will be = 60 t + 60

But as per given in question, total distance covered by both is 240 miles.

Hence making both equal,

60 t + 60 = 240

Subtracting 60 from both sides

60 t + 60 - 60 = 240 - 60

60 t = 180

Dividing 60 in both sides

\frac{60 t }{60}  = \frac{180}{60}

t = 3 hrs

It means it was 11:00 AM + 3 hrs means 2:00 PM when dispatcher retrieve data. : Answer

Hope it will help :)

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What is the surface area of the cylinder in terms of ? The diagram is not drawn to scale.
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<u>Symbols</u>

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<em>r</em> = 11 in

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  2. Evaluate exponents:                                                                                         SA = 2π(11 in)(23 in) + 2π(121 in²)
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