Using the two kinematic equations that can be used for this problem are:
Vf = Vi + at and d=Vit +(1/2)*at^2
Since Vi (initial velocity) = 0
The equations can further be simplified where a is the acceleration, t is the time, Vf is the final velocity which is 70 miles per hour and d is 6 miles
Vf = at
70 = at
a = 70/t---equation 1
d=(1/2)*a*(t^2)
6 = (1/2)*a*(t^2) ---equation 2
Substituting equation 1 to equation 2.
6= (1/2)*(70/t)*(t^2)
6= 35t
t= 0.17142 hours or 10.28571 mins or 617.14 sec
-- If the field were inclined to the surface, then it would have
some component parallel to the surface.
-- Then, since we're talking about a conductor, the charges
on the object would move in response to that component
of the field, until there was no longer any component of the
field trying to move them.
The answer is:
Transverse dune
The explanation:
Transverse dune : is abundant barchan dunes It may merge into barchanoid ridges, which then grade into linear .
The transverse dunes is called that because they lie transverse, or across, the wind direction, with the wind blowing perpendicular to the ridge crest.
It is large, very asymmetrical, elongated dune lying at right angles 90° to the prevailing wind direction.
Transverse dunes have a gently sloping windward side and a steeply sloping leeward side.
They general form in areas of sparse vegetation and abundant sand are transverse dunes.
Answer:
A theory is a system of ideas intended to explain something, and a hypothesis is an educated guess.
Explanation: Hope this Helps! :)
