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4 years ago

How many neutrons does element x have if it’s atomic number is 23 and it’s mass is 90

Physics

1 answer:

Oxana [17]4 years ago

3 0

The amount of neutrons would be 23.

The atomic number represents the amount of neutrons, so all you have to do is look at it to know. The atomic mass was put here simply to mislead you. B.T.W, the element is Valadium.

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Which statement correctly describes a hypothesis?

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Answer:

Explanation:

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4 years ago

What happens inside when an air-filled, sealed can, is heated?.

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2 years ago

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A boat was traveling at 15 mph when a passenger threw an object at 10 mph in the same direction the boat was moving. A friend,

Slav-nsk [51]

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3 years ago

The closeness of measured values to an accepted value is the BLANK of the data ?

wlad13 [49]

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3 years ago

he fan blades on a jet engine make one thousand revolutions in a time of 54.9 ms. What is the angular frequency of the blades?

Gnesinka [82]

So, the angular frequency of the blades approximately <u>36.43π rad/s</u>.

<h3>Introduction</h3>

Hi ! Here I will discuss about the angular frequency or what is also often called the angular velocity because it has the same unit dimensions. <u>Angular frequency occurs, when an object vibrates (either moving harmoniously / oscillating or moving in a circle)</u>. Angular frequency can be roughly interpreted as the magnitude of the change in angle (in units of rad) per unit time. So, based on this understanding, the angular frequency can be calculated using the equation :

$\boxed{\sf{\bold{\omega = \frac{\theta}{t}}}}$

With the following condition :

$\sf{\omega}$ = angular frequency (rad/s)
$\sf{\theta}$ = change of angle value (rad)
t = interval of the time (s)

<h3>Problem Solving</h3>

We know that :

$\sf{\theta}$ = change of angle value = 1,000 revolution = 1,000 × 2π rad = 2,000π rad/s >> Remember 1 rev = 2π rad/s.
t = interval of the time = 54.9 s.

What was asked :

$\sf{\omega}$ = angular frequency = ... rad/s

Step by step :

$\sf{\omega = \frac{\theta}{t}}$

$\sf{\omega = \frac{2,000 \pi}{54.9}}$

$\boxed{\sf{\omega \approx 36.43 \pi \: rad/s}}$

<h3>Conclusion :</h3>

So, the angular frequency of the blades approximately 36.43π rad/s.

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2 years ago