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3 years ago

What does AS>0 mean?| I

Physics

2 answers:

bulgar [2K]3 years ago

8 0

Significant other hope it helped

tigry1 [53]3 years ago

5 0

Answer:

Significant Other

Explanation:

that comes to mind when I see that

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Water, in a 100-mm-diameter jet with speed of 30 m/s to the right, is deflected by a cone that moves to the left at 14 m/s. Dete

podryga [215]

Answer:

Explanation:

The velocity at the inlet and exit of the control volume are same $V_i=V_e=V$

Calculate the inlet and exit velocity of water jet

$V=V_j+V_e\\\\V=30+14\\\\V=44m/s$

The conservation of mass equation of steady flow

$\sum ^e_i\bar V. \bar A=0\\\\(-V_iA_i+V_eA_e)=0$

$A_i\ \texttt {is the inlet area of the jet}$

$A_e\ \texttt {is the exit area of the jet}$

since inlet and exit velocity of water jet are equal so the inlet and exit cross section area of the jet is equal

The expression for thickness of the jet

$A_i=A_e\\\\\frac{\pi}{4} D_j^2=2\pi Rt\\\\t=\frac{D^2_j}{8R}$

R is the radius

t is the thickness of the jet

D_j is the diameter of the inlet jet

$t=\frac{(100\times10^{-3})^2}{8(230\times10^{-3}} \\\\=5.434mm$

(b)

$R-x=\rho(AV_r)[-(V_i)+(V_c)\cos 60^o]\\\\=\rho(V_j+V_c)A[-(V_i+V_c)+(V_i+V_c)\cos 60^o]\\\\=\rho(V_j+V_c)(\frac{\pi}{4}D_j^2 )[V_i+V_c](\cos60^o-1)]$

$1000kg/m^3=\rho\\\\44m/s=(V_j+V+c)\\\\100\times10^{-3}m=D_j$

$R_x=[1000\times(44)\frac{\pi}{4} (10\times10^{-3})^2[(44)(\cos60^o-1)]]\\\\=-7603N$

The negative sign indicate that the direction of the force will be in opposite direction of our assumption

Therefore, the horizontal force is -7603N

7 0

3 years ago

A 243 mL cup of whole milk contains about 45 mg of cholesterol. Express the cholesterol concentration of the milk in kilograms p

timama [110]

Answer: $0.1851 \frac{kg}{m^{3}}$

Explanation:

We have this concentration in units of $mg/ml$ :

$\frac{45 mg}{243 ml}$

And we need to express it in $kg/m^{3}$ , knowing:

$1 ml= 1 cm^{3}$

$1 m^{3}= (100 cm) ^{3}$

$1g = 1000 mg$

$1 kg = 1000 g$

Hence:

$\frac{45 mg}{243 cm^{3}} \frac{1 g}{1000 mg} \frac{1 kg}{1000 g} \frac{(100 cm) ^{3}}{1 m^{3}}=0.1851 \frac{kg}{m^{3}}$

5 0

3 years ago

How many does the stor6 need

melomori [17]

I there supposed to be a picture here or

3 0

2 years ago

The energy absorbed or released during a reaction in which a substance is produced is called the

sweet [91]

the answer is bond energy but I am not pretty sure

7 0

3 years ago

Given 1 inch ≡ 2.54 cm and 1 foot ≡

d1i1m1o1n [39]

Answer:

2991.47 [cm^2]

Explanation:

To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:

$3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}]$

3 0

3 years ago