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Vikki [24]
2 years ago
15

A t-rated switch may be used to (its/a) ______ current capacity when controlling an incandescent lighting load.

Physics
1 answer:
jok3333 [9.3K]2 years ago
6 0

<u>Rated </u>

A t-rated switch may be used to (its/a) <u>Rated</u> current capacity current capacity when controlling an incandescent lighting load.

<h3>What is "current rating"?</h3>
  • The greatest current that a fuse is rated to carry for an infinite duration without significantly degrading the fuse element is known as the current rating.
  • There is also a large selection of power switching transistors that have voltage ratings well over 1000V and current ratings up to several hundred amps.

<h3>What does the term "rated current" mean?</h3>
  • When an electrical device receives its rated voltage and outputs its rated power, it flows at its rated current.
  • So, when a device is designed for a certain amperage, that amperage is referred to as the equipment's rated current.

<h3>What does electrical "rated" mean?</h3>
  • An electrical appliance's rating reveals the voltage range at which it is intended to operate as well as the current consumption at that range.
  • These numbers are typically shown on a rating plate that is fastened to the device, such as 230 volts, 3 amps.

To learn more about current capacity visit:

brainly.com/question/27987428

#SPJ4

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3 years ago
Classyfying— what is the name of the force you exert on a sponge when you squeeze it?
Kruka [31]
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5 0
3 years ago
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Approximate the Sun as a uniform sphere of radius 6.96 X 108 m, rotating about its central axis with a period of 25.4 days. Supp
In-s [12.5K]

Answer:

T = 184 seconds

Explanation:

First in order to solve this, we need to know which is the expression to calculate the period. This is an exercise of angular velocity, so:

T = 2π/w

Where w: angular speed (in rad/s)

So, let's calculate first the innitial angular speed:

w = 2π/T

Converting days to seconds:

25.4 days * 24 h/day * 3600 s/h = 2,194,560 s

Then the angular speed:

w = 2π / 2,194,560 = 2.863x10^-6 rad/s

Now, the innitial angular momentum is:

I = (2/5)Mr² replacing data:

I = 2/5* (6.96x10^8)² * M = 1.94x10^17m² * M

so the initial angular momentum would be:

L = Iω = 2.863x10^-6 * 1.94x10^17 M

L = 5.55x10^11 m²/s * M = final angular momentum

Now the  final I = 2/5Mr²

Final I = 2/5 * (6.37x10^6)² * M  = 1.62x10^13m² * M

Then 5.55x10^11m²/s * M = 1.62x10^13m² * M * ω → M cancels

ω = 3.42x10^-2 rad/s

Then the new period

T = 2π/ω = 2*3.14 / 3.42x10^-2

T = 184 seconds

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3 years ago
A box is being pulled to the right. What is the direction of the gravitational force?
lapo4ka [179]

The correct answer to the question is vertically downward i.e towards the centre of earth.

EXPLANATION:

As per the question, the box is pulled to the right.

Hence, the direction of the applied force is towards right.

We are asked to determine the direction of the gravitational force that acts on the body.

Before answering this question, first we gave to understand the gravitational force of earth.

Any body present on the surface of earth is attracted with the force of gravity of earth ( gravitational force ) towards its centre.  It is equivalent to the weight of the body.  

The force of gravity is always directed towards the centre of earth irrespective of the nature of applied force.

Hence, the direction of the gravitational force which acts on the box is vertically downward.


7 0
3 years ago
Read 2 more answers
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