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Vikki [24]
1 year ago
15

A t-rated switch may be used to (its/a) ______ current capacity when controlling an incandescent lighting load.

Physics
1 answer:
jok3333 [9.3K]1 year ago
6 0

<u>Rated </u>

A t-rated switch may be used to (its/a) <u>Rated</u> current capacity current capacity when controlling an incandescent lighting load.

<h3>What is "current rating"?</h3>
  • The greatest current that a fuse is rated to carry for an infinite duration without significantly degrading the fuse element is known as the current rating.
  • There is also a large selection of power switching transistors that have voltage ratings well over 1000V and current ratings up to several hundred amps.

<h3>What does the term "rated current" mean?</h3>
  • When an electrical device receives its rated voltage and outputs its rated power, it flows at its rated current.
  • So, when a device is designed for a certain amperage, that amperage is referred to as the equipment's rated current.

<h3>What does electrical "rated" mean?</h3>
  • An electrical appliance's rating reveals the voltage range at which it is intended to operate as well as the current consumption at that range.
  • These numbers are typically shown on a rating plate that is fastened to the device, such as 230 volts, 3 amps.

To learn more about current capacity visit:

brainly.com/question/27987428

#SPJ4

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Hi there!

We can use the following kinematic equation:

v_f^2 = v_i^2 + 2ad

vf = final velocity (? m/s)
vi = intial velocity (0 m/s)

a = acceleration (5 m/s²)

d = displacement (8 m)

Plug in the givens and solve.

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Light of wavelength 500 nm is incident perpendicularly from air on a film 10-4cm thick and of refractive index 1.375. Part of th
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Answer

given,

wavelength (λ)= 500 n m

thickness of film= 10⁻⁴ cm

refractive index = μ = 1.375

distance traveled is double which is equal to 2 x 10⁻⁴ cm

a) Number of wave

     N = \dfrac{d}{\mu\lambda}

     N = \dfrac{2 \times 10^{-6}}{1.375\times 500 \times 10^{-9}}

           N = 2.91

           N = 3

b) phase difference is equal to

Reflection from the first surface has a 180° (½λ) phase change.

There is no phase change for the 2nd surface reflection and there is no phase difference for the 2nd wave having traveled an exact whole number of waves.

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