Question

State the amplitude, period, and phase shift for y=2sin3(x-π/4)

Answer 1

Answer:

Amplitude 2

Period: $\frac{2\pi}{3}$

Phase shift: $\frac{\pi}{4}$ units to the right

Step-by-step explanation:

The given function is $y=2\sin(3(x-\frac{\pi}{4}))$

This function is of the form $y=A\sin(Bx+C)$

where $A=|2|=2$ is the amplitude.

The period is $\frac{2\pi}{B}= \frac{2\pi}{3}$

This function is shifted $\frac{\pi}{4}$ units to the right