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3 years ago

What could be a word problem for numbers -8 and 5

Mathematics

1 answer:

Marat540 [252]3 years ago

8 0

Answer:

A whale is located 8 ft. below sea level. A seagull is flying 5 ft. above sea level. What is the distance between the whale and the seagull?

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Help me pls I’ve been posting this question all day

Rama09 [41]

Answer:

19.5 sq. inches

Step-by-step explanation:

This one is fairly simple. The area of a rhombus is the same as that of a parallelogram, which is side * height. In this case, we have 6.5 (side) *3 (height) = 19.5 sq. inches. Hope this helps!

6 0

3 years ago

A used motorcycle is on sale for $3,600. Erik makes an offer equal to 3/4 of this price. How much does Erik offer for the motorc

lesantik [10]

3/4 of 3600..." of " means multiply
3/4 * 3600 =
10800/4 =
2700 <==

4 0

3 years ago

Read 2 more answers

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

$\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666$

Second step. <u>Calculate the standard deviation</u>

$\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}$

$\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}$

$\sigma=\sqrt{17.815}=4.22$

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

$\bar X \pm t\frac{\sigma}{\sqrt n}$

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0

3 years ago

How to solve -8+squre root (5a-5)=-3

sertanlavr [38]

Answer:

$a=6$

Step-by-step explanation:

Given equation:

$-8+\sqrt{5a-5}=-3$

Solving for unknown variable $a$

Adding 8 both sides by additive property of equality.

$+8-8+\sqrt{5a-5}=-3+8$

$\sqrt{5a-5}=5$

Squaring both sides to remove the square root.

$(\sqrt{5a-5})^2=5^2$

$5a-5=25$

Adding 5 both sides by additive property of equality.

$5a-5+5=25+5$

$5a=30$

Dividing both sides by 6 to isolate $a$

$\frac{5a}{5}=\frac{30}{5}$

∴ $a=6$

8 0

3 years ago

Help please!!!!

Sonja [21]

Answer:

you already put this one

6 0

3 years ago