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aniked [119]
4 years ago
7

Find the 11th term of this sequence. -10,20,-40,80...

Mathematics
2 answers:
Morgarella [4.7K]4 years ago
6 0
The difference is not constant therefore there cannot be an 11th term that is correct.

Pani-rosa [81]4 years ago
5 0

Answer:

-10240

Step-by-step explanation:

Look at the numbers. (-10(-2) = 20. (20)(-2) is -40. (-40)(-2) is 80. Keep multiplying it by -2 to get your 11th term.

If done correctly, your answer is -10240

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Find the percent of change. Round to the nearest percent.
katovenus [111]

Answer:

<u> -54.5%</u>

Step-by-step explanation:

You will have to use this formula

\frac{new value-oldvalue}{oldvalue}

When substituted in you have \frac{30-66}{66}

30-66=-36

-36/66= -0.54 (54 repeating)

Then you have to convert this into a percentage, -54.54(repeating) percent

To the nearest hundredth you would round down to<u> -54.5%</u>.

It is a Decrease because it is negatated.

8 0
3 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
Salma is in charge of decorating the school gym for a party. She has budgeted some money for decorations. Balloons (x) cost $2.5
Artyom0805 [142]

Answer:

your answer would be A.

Step-by-step explanation:

Already you know that answers b and d are not an option because it is saying she can use OVER 45 dollars. So she has to use EQUAL or less then 45 dollars. So the answer has to be A or C. In answer C it is saying she can spend MORE then 2.50 for a bunch where she cant. She has to spend exactly or less then that amount. So your answer is A.

5 0
3 years ago
While riding her bike to the ocean and back home 5 times, Kimberly timed herself at 53min, 48min, 56min, 54min, and 45min. She h
alex41 [277]

Answer:

Kim will need to spend 67 minutes on her sixth ride

Step-by-step explanation:

Represent the number of minutes of her sixth ride by m.

Then the average number of minutes is

53 + 43 + 56 + 54 + 45 + m

---------------------------------------- = 53

                      6

Multiplying both sides of this equation by 6 yields

6(53 + 43 + 56 + 54 + 45 + m)

--------------------------------------------- = 6(53)

                        6

which simplifies to

 251 + m

---------------- = 318

         

or  251 + m = 318.  Subtract 251 from both sides to obtain the value of m:

m  = 318 - 251 = 67

Kim will need to spend 67 minutes on her sixth ride to attain an average ride length of  53 minutes.i

4 0
3 years ago
If all accounts earn 1.5% interest per year and no further deposits are made, how much will Letisha have earned one year after h
aleksandrvk [35]
<span>Letisha will have earned however much money she began with plus 1.5 percent. This can be found by taking the initial principal on January 1 of the previous year, multiplying it by 0.015, and adding the result to the previous balance to get the end-of-year total.</span>
4 0
3 years ago
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