Answer:
A. x = 11/16
Step-by-step explanation:
For the purpose here, it is convenient to rearrange the equation to f(x) -g(x) = 0. We know the root will be in the interval [0, 1] because (f-g)(0) = -3 and (f-g)(1) = +3. At each iteration, we evaluate (f-g)(x) at the midpoint of the interval to see which of the interval end points can be moved and still bracket the root.
Using the bisection method starting with the interval [0, 1] we find f(1/2)-g(1/2) < 0, so we can move the interval limits to [1/2, 1].
For the next iteration, we find f(3/4) -g(3/4) > 0, so we can move the interval limits to [1/2, 3/4].
For the third iteration, we find f(5/8) -g(5/8) < 0, so we can move the interval limits to [5/8, 3/4].
Then the root is approximately the middle of that interval:
x ≈ (5/8 +3/4)/2 = 11/16
_____
This value of x is 0.6875. The root is closer to 0.639802004233. The bisection method takes about 3 iterations for each decimal place of accuracy. Other methods can nearly double the number of accurate decimal places on each iteration.
So to help with the first one
2 / x = 5
multiply the x on both sides
2 = 5x
divide by 5 to isolate the x
2/5 = x
For the second one
We will use the diamond to help us find the common factor
\ 1 /
\ /
\ /
2 / \ 4
/ 3 \
/ \
1) the product
2) and 4) the two numbers
and 3) is sum
10 is the product and -7 is the sum
so what two numbers (factors of 10)
will equal -7 when added
so we have these numbers that will equal the product of +10 and we will need to find the ones that will equal -7 as the sum
10*1, 2*5, -1*-10, -2*-5
if we add the two numbers we will find respectively
11, 7, -11, -7
As you can see that -2 + -5 = +10 and -2+-5= +10
So we have found the two numbers
now before we factor the expression looks like
( x + a) (x + b)
and when factored looks like
x^2 + (a+b)x + (a*b)
Now we can plug in the numbers and solve to see if -2 and -5 are right
(x + -2) (x + -5)
we will factor it
x^2 +-5x + -2x + 10
x^2 + -7x + 10
so a = -2 and b = -5
Hope this helps :)
That would be FALSE.
The median is a robust statistic that can only move a little bit even given the largest outlier. A single outlier can affect the mean, the average, arbitrarily much.
When Bill Gates gives a talk at a school of 1000 people, the average wealth of the people in the school goes up by millions, but the median wealth of the people in the school hardly changes at all.
Answer:
A.
Step-by-step explanation:
( 5,0)
When x axises is a reflection in the y axis
I think the on in the top right is the answer.
