Answer
A, C, and D
Step-by-step explanation:
You are trying to find the y value in (x,y) form. Therefore, it has to be A, C, and D because they all have a 6 in the y value.
Javier rode his bike for a total of 40 minutes.
Let x be the minutes Javier ride after lunch
Let y be the minutes Javier ride before lunch
The number of minutes he rode after lunch is 4 times the number of minutes he rode before lunch
x = 4 y
The number of minutes he rode after lunch + number of minutes he rode before lunch = 40
x + y = 40
We know x= 4y
4y + y = 40
5y = 40
y = 8
x= 4y so x= 4(8) = 32
Javier ride 32 minutes after lunch
There are 210 different possible combinations
<h3>How to determine the number of possible combinations?</h3>
The given parameters are:
- Types of candy, n = 10
- Candies to taste, r = 6
The number of possible combinations is calculated using:
Combination = nCr
This gives
Combination = 10C6
Apply the combination formula
Combination = (10!)/((10 - 6)!6!)
Evaluate
Combination = 210
Hence, there are 210 different possible combinations
Read more about combination at:
brainly.com/question/11732255
Answer:
Option D. ![\sqrt[4]{\frac{3x^{2}}{2y}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B2y%7D%7D)
Step-by-step explanation:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D)
![\sqrt[4]{(\frac{24}{128})\times (\frac{x^{6}}{x^{4}})\times (\frac{y}{y^{5}})}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B24%7D%7B128%7D%29%5Ctimes%20%28%5Cfrac%7Bx%5E%7B6%7D%7D%7Bx%5E%7B4%7D%7D%29%5Ctimes%20%28%5Cfrac%7By%7D%7By%5E%7B5%7D%7D%29%7D)
= ![\sqrt[4]{(\frac{3}{16})\times {(x)^{6-4}}\times{(y)^{1-5}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B3%7D%7B16%7D%29%5Ctimes%20%7B%28x%29%5E%7B6-4%7D%7D%5Ctimes%7B%28y%29%5E%7B1-5%7D%7D%7D)
= ![\sqrt[4]{(\frac{3}{16})\times x^{2}y^{-4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B3%7D%7B16%7D%29%5Ctimes%20x%5E%7B2%7Dy%5E%7B-4%7D%7D)
= ![\sqrt[4]{\frac{3}{(2)^{4}}\times x\times y^{-4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3%7D%7B%282%29%5E%7B4%7D%7D%5Ctimes%20x%5Ctimes%20y%5E%7B-4%7D%7D)
= ![\sqrt[4]{(3\times x^{2)\times (\frac{y^{-1}}{2})^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%283%5Ctimes%20x%5E%7B2%29%5Ctimes%20%28%5Cfrac%7By%5E%7B-1%7D%7D%7B2%7D%29%5E%7B4%7D%7D%7D)
= ![\frac{y^{-1}}{2}\sqrt[4]{3x^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7By%5E%7B-1%7D%7D%7B2%7D%5Csqrt%5B4%5D%7B3x%5E%7B2%7D%7D)
=
Option D. is the correct answer.
Answer:
10 square units
Step-by-step explanation:
We want to find the area under the curve 
from x=1 to x=3.
We use definite integrals to find this area.
We integrate to obtain:
We evaluate the limits to get:
Therefore the area under the curve from x=1 to x=3 is 10 square unit.
