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galben [10]
3 years ago
12

I really need help with my question ​

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0

The answer would be B

______________________

y = x - 5

would be 5 units below

y = x

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Factor: 3x^2 - 288y^2 - 36
erica [24]

Answer:

3x^2-288y^2-36

Rewrite -36 as 12×3

Rewrite -288 as 96×3

3x^2+96.3y^2+12.3

factor out common term 3

=3(x^2-96y^2-12)

7 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-1,7) and is parallel to the line y= -2x-1
Nuetrik [128]

if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, \bf y=\stackrel{slope}{-2}x-1 has a slope of -2.


now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.


\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope =  m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5

3 0
3 years ago
a childrens book has dimensions 20cm by 24cm what scale factor should be used to make a enlarged version that has dimensions 25c
SSSSS [86.1K]
A scale factor of 1.25, also written as 1 1/4 should be used
5 0
3 years ago
KL = 4x+7 and LM= 5x-4
saul85 [17]
4x+7=5x-4
-4x     -4x
7=x-4
+4   +4
11=x
6 0
3 years ago
Read 2 more answers
Consider the case of a triangle with sides 5, 12, and the angle between them 90°.
Daniel [21]

Answer:

a) Applying Pithagoras Theorem

b) Trigonometric relations

c) No we can not

d) No we can not

e) See step-by-step explanation

f) See step-by-step-explanation

Step-by-step explanation:

a) The easiest method for calculating the missing side is applying Pithagoras Theorem

c²  =  a²  +  b²

c²  =  (5)²  +  (12)²      ⇒  c²  = 25 + 144    ⇒ c²  =  169    ⇒  c  = 13

b) The easiest method to find the missing angles, is to calculate the sin∠ and then look for arcsin fuction in tables.

sin ∠α = 5/13    sin ∠α = 0.3846    ⇒      arcsin (0.3846 )   α  = 23⁰

Now we can either get the other angle subtracting 180 - 90 - 23 = 67⁰

Or calculating sinβ = 12 /13    sinβ = 0.9230  arcsin(0.9230)   β = 67⁰

c) The law of cosines should not be applied to right triangles, in fact for instance in our particular case we have:

Question a)

c²  = a² + b² - 2*a*b*cos90⁰   (law of cosines ) but cos 90⁰ = 0

then c²  = a² + b² which is the expression for theorem of Pithagoras

In case you look for calculating the missing angles

c²  = a²  +  b²  - 2*5*13*cos α

169 = 25  +  144 - 2*5*13* cos α

As you can see 169 - 25 - 144 = 0

Then we can not  apply law of cosine in right triangles, we shoul apply trigonometric relations and Pithagoras theorem, and as we saw you can get the expression of Pithagoras theorem from cosine law

c²  =  a²  +  b²  - 2*a*b*cos∠90°    cos ∠ 90°  = 0

Then     c²  =  a²  +  b²

3 0
3 years ago
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