If the side of square P is x and the side of square Q is y, we have x+y=26. In addition, 3*the perimeter of P+8*4y=3*4x+32y=12x+32y=492.
We have
x+y=26
12x+32y=492
Multiplying the first equation by -12 and adding it to the second, we get
20y=180 and dividing by 20 we get y=9. Plugging it into the first equation, we get 26-9=17=x. Since the area of square P is x^2 and Q is y^2,
x^2+y^2=19^2+7^2=410=the sum of the squares
Answer:
Step-by-step explanation:
Both triangles in this figure are similar. Therefore, we can set up the following proportion:
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Cross-multiply to solve:
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A right triangle contains a right angle, so it must have two sides that are perpendicular. If the slopes of two sides can be shown to be negative reciprocals of each other, then it can be concluded that a right angle is formed. If a triangle contains a right angle, then it is a right triangle.
