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Alla [95]
3 years ago
6

What animal is perry the platypus ​

Computers and Technology
2 answers:
valkas [14]3 years ago
8 0

Answer:

A Platypus. Its in the name XDDD

Explanation:

valkas [14]3 years ago
4 0

Answer: Agent P or simply Perry

Explanation:

You might be interested in
Write a class called DisArray with methods to convert a 1-dimensional array to a 2-dimensional array. The methods' name should b
meriva
<h2>Answer:</h2>

=======================================================

//Class header definition

public class DisArray {

   //First method with int array as parameter

   public static void convert2D(int[] oneD) {

       //1. First calculate the number of columns

       //a. get the length of the one dimensional array

       int arraylength = oneD.length;

       //b. find the square root of the length and typecast it into a float

       float squareroot = (float) Math.sqrt(arraylength);

       //c. round off the result and save in a variable called row

       int row = Math.round(squareroot);

       //2. Secondly, calculate the number of columns

       //a. if the square of the number of rows is greater than or equal to the

       //length of  the one dimensional array,

       //then to minimize padding, the number of

       //columns  is the same as the number of rows.

       //b. otherwise, the number of columns in one more than the

       // number of rows

       int col = ((row * row) >= arraylength) ? row : row + 1;

       //3. Create a 2D int array with the number of rows and cols

       int [ ][ ] twoD = new int [row][col];

       //4. Place the elements in the one dimensional array into

       //the two dimensional array.

       //a. First create a variable counter to control the cycle through the one

       // dimensional array.

       int counter = 0;

       //b. Create two for loops to loop through the rows and columns of the

       // two  dimensional array.

       for (int i = 0; i < row; i++) {

           for (int j = 0; j < col; j++) {

               //if counter is less then the length of the one dimensional array,

               //then  copy the element at that position into the two dimensional

               //array.  And also increment counter by one.

               if (counter < oneD.length) {

                   twoD[i][j] = oneD[counter];

                   counter++;

              }

              //Otherwise, just pad the array with zeros

               else {

                   twoD[i][j] = 0;

               }

           }

       }

       //You might want to create another pair of loop to print the elements

       //in the  populated two dimensional array as follows

       for (int i = 0; i < twoD.length; i++) {

           for (int j = 0; j < twoD[i].length; j++) {

               System.out.print(twoD[i][j] + " ");

           }

           System.out.println("");

       }

   }     //End of first method

   //Second method with String array as parameter

   public static void convert2D(String[] oneD) {

       //1. First calculate the number of columns

       //a. get the length of the one dimensional array

       int arraylength = oneD.length;

       //b. find the square root of the length and typecast it into a float

       float squareroot = (float) Math.sqrt(arraylength);

       //c. round off the result and save in a variable called row

       int row = Math.round(squareroot);

       //2. Secondly, calculate the number of columns

       //a. if the square of the number of rows is greater than or equal to the length of  

       //the one dimensional array, then to minimize padding, the number of

       //columns  is the same as the number of rows.

       //b. otherwise, the number of columns in one more than the

       //number of rows.

       int col = (row * row >= arraylength) ? row : row + 1;

       //3. Create a 2D String array with the number of rows and cols

       String[][] twoD = new String[row][col];

       //4. Place the elements in the one dimensional array into the two

       // dimensional array.

       //a. First create a variable counter to control the cycle through the one

       // dimensional array.

       int counter = 0;

       //b. Create two for loops to loop through the rows and columns of the

       //two  dimensional array.

       for (int i = 0; i < row; i++) {

           for (int j = 0; j < col; j++) {

               //if counter is less then the length of the one dimensional array,

               //then  copy the element at that position into the two dimensional

               //array.  And also increment counter by one.

               if (counter < oneD.length) {

                   twoD[i][j] = oneD[counter];

                   counter++;

               }

               //Otherwise, just pad the array with null values

               else {

                   twoD[i][j] = null;

               }

           }

       }

       //You might want to create another pair of loop to print the elements  

       //in the populated two dimensional array as follows:

       for (int i = 0; i < twoD.length; i++) {

           for (int j = 0; j < twoD[i].length; j++) {

               System.out.print(twoD[i][j] + " ");

           }

           System.out.println("");

       }

   }    // End of the second method

   //Create the main method

   public static void main(String[] args) {

       //1. Create an arbitrary one dimensional int array

       int[] x = {23, 3, 4, 3, 2, 4, 3, 3, 5, 6, 5, 3, 5, 5, 6, 3};

       //2. Create an arbitrary two dimensional String array

       String[] names = {"abc", "john", "dow", "doe", "xyz"};

       

       //Call the respective methods

       convert2D(x);

       System.out.println("");

       convert2D(names);

   }         // End of the main method

}            // End of class definition

=========================================================

==========================================================

<h2>Sample Output</h2>

23 3 4 3  

2 4 3 3  

5 6 5 3  

5 5 6 3  

abc john dow  

doe xyz null

==========================================================

<h2>Explanation:</h2>

The above code has been written in Java and it contains comments explaining each line of the code. Please go through the comments. The actual executable lines of code are written in bold-face to distinguish them from the comments.

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A hardware company is considering adopting customer relationship management solutions. What are the possible advantages the comp
irinina [24]

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Finding customers for your business is not easy. And once you find them, there comes another challenge – Establishing and maintaining strong relationships with them.

CRM software helps you centralize, optimize and streamline your communication. The better you know your customers, the stronger your relationships will be with them.

Here, we share 6 CRM benefits that focus on key customer relationship areas, allowing you to offer high-quality, consistent and timely interactions with your customers.

Explanation:

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A technician is installing a server using a two-channel RAID controller, using RAID1 for the first channel and RAID5 for the sec
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Answer:

Two disks RAID 1 and four disks RAID 5.

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The RAID level 1 writes data on both main disk and mirror disk. It is more efficient with only two disk. The RAID 5 strips data across disk array and stores a parity check on them. It can hold 16 disks efficient and can be used in the two channel RAID to hold the remaining four disks.

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3 years ago
Write a set of directions that tells an operating system’s dispatcher what to do when a process time slice is over.
tatyana61 [14]
<span> Directions that tells an operating system's dispatcher what to do when a process's time slice is over.Wait for the interrupt handler to be execute. Allow the scheduler to update the process table. Select the process form the process table that has the highest priority, restart the time, and allow the selected process to begin its time slice. Directions that tells an operating system's dispatcher what to do when a process's time slice is over. Signal an interrupt, save the current position, execute the current position, execute the interrupt handler, and switch to the next process until the process or processes is complete. If a process executes an I/O request, the time slice of that process will be terminated because it would waste the remaining time waiting for the controller to perform the request. A situation in a time-sharing system in which a process does not consume the entire time slice allotted to it. Client/server model Defines the basic roles played by the processes as being that of either a client, which makes requests of other processes Components of the email address </span>
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Sure why not

Explanation:

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