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Solnce55 [7]
3 years ago
15

The bottom of a ladder must be placed 2 1/2 feet from the wall. The ladder is 9 feet long How far above ground is the ladder tou

ch the wall?
Mathematics
2 answers:
Gnoma [55]3 years ago
7 0

Answer:

Step-by-step explanation:

h=\sqrt{9^2-(\frac{5}{2} )^2}\\=\sqrt{81-\frac{25}{4} } \\=\sqrt{\frac{299}{4} } \\=\frac{\sqrt{299} }{2} \\\approx 8.6458\\\approx 8.65 ~ft

UNO [17]3 years ago
4 0

Answer:

24

Step-by-step explanation:

Use the Pythagorean Theorem

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What is the correct solution of<br> 4 - 2x = -2<br> +4 +4<br> 2x = 2<br> 2 2<br> x = 6
zepelin [54]
The answer is x=3
Lol
4 0
3 years ago
in a bag of candies there are `3 red candies, 13 green candies, 13 yellow candies, and 13 blue candies. If you choose 1 candy fr
rodikova [14]

Answer:

29/42

Step-by-step explanation:

No. of red candies = 3

No. of green candies = 13

No. of yellow candies = 13

No. of blue candies = 13

T.T = 42

Probability that candy will not be blue= 13+13+3 = 29

= 29/42

Hope it helps!

Pls mark me brainliest

Have a good day.

8 0
3 years ago
An architect makes a model of a new house. The model shows a tile patio in the backyard. In the​ model, each tile has length
zvonat [6]

The two ways to find the ratio of the length is to turn the inches into feet or the feet into inches

So the answer can be solved like this:

1/36ft to 1/4ft which is 9:1 (blueprint size to actual size)

or

1/3in to 3in which is also 9:1 (blueprint size to actual size)

3 0
3 years ago
Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
suter [353]

Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

\theta = 30^\circ, 330^\circ

Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}

\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

8 0
2 years ago
F(x) = x² – 3x; Find f(-8)
Shtirlitz [24]
F(-8)=8^2-3(-8)
=64+24
=88

Hope this can help.
7 0
3 years ago
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